Molecular Equation: (NaOCI (aq) + 2 KI (aq) +2 HCI (aq) → 12(aq) + 2 KCI (aq) + NacI (aq) + H2O (1) (1a) colorless reddish-brown colorless Net lonic Equation: OCc - (aq) + 21-(aq) + 2 H* (aq) → 12 (aq) + CI- (aq) + H20 (1) (1b) colorless colorless colorless reddish- brown colorless By measuring the amount of I2 produced by this reaction when a known volume of bleach reacts with an excess amount of I-, the amount of OCl- initially present in the bleach can be determined. The amount of I2 produced by reaction (1) can be determined by titrating the reaction mixture with a solution of sodium thiosulfate, Na2S2O3. The titration reaction is given below.

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Molecular Equation:
|N2OCI (aq) + 2 KI (aq) +2 HCI (aq) /
→ 12 (aq) +
2 KCI (aq) +
Nacl (aq) + H2O
Н-О () (1а)
colorless
reddish-brown
colorless
Net lonic Equation:
OCI - (ag) + 21-(aq) + 2 H* (ag)
→ 12 (aq) +
CI (aq) + H2O (I)
(1b)
colorless
colorless
colorless
reddish- brown
colorless
By measuring the amount of l2 produced by this reaction when a known volume of bleach reacts
the amount of OCI- initially present in the bleach can be
with an excess amount of I -
determined.
The amount of I2 produced by reaction (1) can be determined by titrating the reaction mixture
with a solution of sodium thiosulfate, Na2S203. The titration reaction is given below.
Transcribed Image Text:Molecular Equation: |N2OCI (aq) + 2 KI (aq) +2 HCI (aq) / → 12 (aq) + 2 KCI (aq) + Nacl (aq) + H2O Н-О () (1а) colorless reddish-brown colorless Net lonic Equation: OCI - (ag) + 21-(aq) + 2 H* (ag) → 12 (aq) + CI (aq) + H2O (I) (1b) colorless colorless colorless reddish- brown colorless By measuring the amount of l2 produced by this reaction when a known volume of bleach reacts the amount of OCI- initially present in the bleach can be with an excess amount of I - determined. The amount of I2 produced by reaction (1) can be determined by titrating the reaction mixture with a solution of sodium thiosulfate, Na2S203. The titration reaction is given below.
How many grams of iodine (12) are produced when 35.00 ml of 0.100 M NaOCl reacts with
25.0 ml of 0.200 M KI (and excess H*)? See Equation 1.
4)
Transcribed Image Text:How many grams of iodine (12) are produced when 35.00 ml of 0.100 M NaOCl reacts with 25.0 ml of 0.200 M KI (and excess H*)? See Equation 1. 4)
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