A solution of phosphoric acid (H:PO4) with a known concentration of 0.250 | M H.PO4 is titrated with a 0.800 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 72.0 mL H:PO: according to the following balanced chemical equation: H:PO4 + 3 NaOH – Na:PO4 + 3 H2O STARTING AMOUNT 7.50 0.250 1000 43.2 3 72.0 0.800 6.75 x 104 1 0.001 0.0675 22.5 67.5 M HSPO4 mol HsPO4 L NAOH M NaOH mol NaOH mL NaOH L H:PO4 mL HsPO4 g H:PO4 g NaOH
A solution of phosphoric acid (H:PO4) with a known concentration of 0.250 | M H.PO4 is titrated with a 0.800 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 72.0 mL H:PO: according to the following balanced chemical equation: H:PO4 + 3 NaOH – Na:PO4 + 3 H2O STARTING AMOUNT 7.50 0.250 1000 43.2 3 72.0 0.800 6.75 x 104 1 0.001 0.0675 22.5 67.5 M HSPO4 mol HsPO4 L NAOH M NaOH mol NaOH mL NaOH L H:PO4 mL HsPO4 g H:PO4 g NaOH
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:A solution of phosphoric acid (H:PO4) with a known concentration of 0.250 | M H.PO4
is titrated with a 0.800 M NaOH solution. How many mL of NaOH are required to
reach the third equivalence point with a starting volume of 72.0 mL H:PO:
according to the following balanced chemical equation:
H:PO4 +
3
NaOH – Na:PO4 +
3
H2O
STARTING AMOUNT
7.50
0.250
1000
43.2
3
72.0
0.800
6.75 x 104
1
0.001
0.0675
22.5
67.5
M H:PO4
mol HsPO4
L NAOH
M NaOH
mol NaOH
mL NaOH
L H:PO4
mL HsPO4
g HsPO4
g NaOH
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