Modify the code to demonstrate (print out, show) each of the values of the iteration before the final root is determined.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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8.
Given this code:
//This a code to determine the root of a function
//The function is (cosx+2)/3
#include<stdio.h>
#include<math.h>
float root(float);
int main()
{
float a[100],b[100],c=100.0;
int i=1,j=0;
b[0]=(cos(0)-3*0+1);
printf("\nEnter a beginning guess:\n");
scanf ("%f",&a[0]);
while(c>0.00001)
{
a[j+1]=root(a[j]);
c=a[j+1]-a[j];
c=fabs(c); //fabs = Absolute Value of Floating-Point Number
j++;
}
printf("\n The root of the given function is %f",a[j]);
}
float root(float x)
{
Transcribed Image Text:8. Given this code: //This a code to determine the root of a function //The function is (cosx+2)/3 #include<stdio.h> #include<math.h> float root(float); int main() { float a[100],b[100],c=100.0; int i=1,j=0; b[0]=(cos(0)-3*0+1); printf("\nEnter a beginning guess:\n"); scanf ("%f",&a[0]); while(c>0.00001) { a[j+1]=root(a[j]); c=a[j+1]-a[j]; c=fabs(c); //fabs = Absolute Value of Floating-Point Number j++; } printf("\n The root of the given function is %f",a[j]); } float root(float x) {
float y;
y=(cos(x)+2)/3;
return y;
}
Modify the code to demonstrate (print out, show) each of the values of the iteration
before the final root is determined.
Transcribed Image Text:float y; y=(cos(x)+2)/3; return y; } Modify the code to demonstrate (print out, show) each of the values of the iteration before the final root is determined.
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