Make absolutely no changes to main(). Change function backwards so that the elements of the array are swapped in order for elements to be in reverse order. That is, arr[0] will be 16, arr[1] will be 5, etc. But backwards() must work no matter what values are in the array and for all values passed in for number. After it is corrected this program should output: 16 5 3 17 8 2 #include using namespace std; void backwards(int [], int); int main() { int arr[] = {2,8,17,3,5,16}; int i; backwards(arr,6); for (i = 0; i< 6; i++) cout<
Make absolutely no changes to main(). Change function backwards so that the elements of the array are swapped in order for elements to be in reverse order. That is, arr[0] will be 16, arr[1] will be 5, etc. But backwards() must work no matter what values are in the array and for all values passed in for number. After it is corrected this
16
5
3
17
8
2
#include <iostream>
using namespace std;
void backwards(int [], int);
int main()
{
int arr[] = {2,8,17,3,5,16}; int i;
backwards(arr,6);
for (i = 0; i< 6; i++)
cout<<arr[i]<<endl;
//system("pause");
return 0;
}
void backwards(int array[], int number)
{
/*Pre: array[] - array of integers
number - number of elements in the array that have values
Post: Nothing
Purpose: Reverse the order of the elements of an array */
int i; int temp;int j;
for(i = 0; i < number;i++)
{
temp = array[i];
array[i] = array[number - 1 - i];
temp = array[number - 1 - i];
}
return;
}
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