Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this: CH₂(g) + 2H₂S(g) → 4H₂(g)+cS₂(g) Use this chemical equation to answer the questions in the table below. Suppose 210. mmol of CH4 and 420. mmol of H₂S are added to an empty flask. How much CH will be in the flask at equilibrium? Suppose 115. mmol of H₂ and 28.8 mmol of CS, are added to an empty flask. How much CH will be in the flask at equilibrium? None. O Some, but less than 210. mmol. ○ 210. mmol. O More than 210. mmol. O None. Some, but less than 28.8 mmol. 28.8 mmol. More than 28.8 mmol.
Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this: CH₂(g) + 2H₂S(g) → 4H₂(g)+cS₂(g) Use this chemical equation to answer the questions in the table below. Suppose 210. mmol of CH4 and 420. mmol of H₂S are added to an empty flask. How much CH will be in the flask at equilibrium? Suppose 115. mmol of H₂ and 28.8 mmol of CS, are added to an empty flask. How much CH will be in the flask at equilibrium? None. O Some, but less than 210. mmol. ○ 210. mmol. O More than 210. mmol. O None. Some, but less than 28.8 mmol. 28.8 mmol. More than 28.8 mmol.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like
this:
CH₂(g) + 2H₂S(g) → 4H₂(g)+CS₂(g)
Use this chemical equation to answer the questions in the table below.
Suppose 210. mmol of CH4 and
420. mmol of H₂S are added to an
empty flask. How much CH will be
in the flask at equilibrium?
Suppose 115. mmol of H₂ and
28.8 mmol of CS₂ are added to an
empty flask. How much CH will be
in the flask at equilibrium?
None.
Some, but less than 210. mmol.
O 210. mmol.
More than 210. mmol.
None.
Some, but less than 28.8 mmol.
28.8 mmol.
O More than 28.8 mmol.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F041265a3-a71e-4241-8310-3be872370763%2F6902ba23-61d0-491a-9ff6-5c6cb7269748%2Frj4dj9s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like
this:
CH₂(g) + 2H₂S(g) → 4H₂(g)+CS₂(g)
Use this chemical equation to answer the questions in the table below.
Suppose 210. mmol of CH4 and
420. mmol of H₂S are added to an
empty flask. How much CH will be
in the flask at equilibrium?
Suppose 115. mmol of H₂ and
28.8 mmol of CS₂ are added to an
empty flask. How much CH will be
in the flask at equilibrium?
None.
Some, but less than 210. mmol.
O 210. mmol.
More than 210. mmol.
None.
Some, but less than 28.8 mmol.
28.8 mmol.
O More than 28.8 mmol.
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