N2(g) + 202(g) → 2NO2(g) A chemist added 0.35 mol of nitrogen gas to 0.45 mol of oxygen gas in 1.0 L container. At equilibrium, the concentration of N2 is 0.30 mol/L. 8. The value of equilibrium concentration of NO2(g) is:

N2(g) + 202(g) → 2NO2(g) A chemist added 0.35 mol of nitrogen gas to 0.45 mol of oxygen gas in 1.0 L container. At equilibrium, the concentration of N2 is 0.30 mol/L. 8. The value of equilibrium concentration of NO2(g) is:

World of Chemistry, 3rd edition

3rd Edition

ISBN:9781133109655

Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Chapter17: Equilibrium

Section: Chapter Questions

Problem 38A

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Question

N2(g) + 202(g) → 2NO2(g)
A chemist added 0.35 mol of nitrogen gas to 0.45 mol of oxygen gas in
1.0 L container. At equilibrium, the concentration of N2 is 0.30 mol/L.
8. The value of equilibrium concentration of NO2(g) is:

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