Nitrogen dioxide and carbon monoxide react to form nitrogen monoxide and carbon dioxide, like this: NO₂(g) + CO (g) →→ NO(g) + CO₂(g) - Use this chemical equation to answer the questions in the table below. Suppose 65.0 mmol of NO2 and 65.0 mmol of CO are added to an empty flask. How much NO₂ will be in the flask at equilibrium? 2 Suppose 215. mmol of NO and 215. mmol of CO₂ are added to an empty flask. How much NO₂ will be in the flask at equilibrium? O None. O Some, but less than 65.0 mmol. 65.0 mmol. More than 65.0 mmol. O None. O Some, but less than 215. mmol. ○ 215. mmol. More than 215. mmol.
Nitrogen dioxide and carbon monoxide react to form nitrogen monoxide and carbon dioxide, like this: NO₂(g) + CO (g) →→ NO(g) + CO₂(g) - Use this chemical equation to answer the questions in the table below. Suppose 65.0 mmol of NO2 and 65.0 mmol of CO are added to an empty flask. How much NO₂ will be in the flask at equilibrium? 2 Suppose 215. mmol of NO and 215. mmol of CO₂ are added to an empty flask. How much NO₂ will be in the flask at equilibrium? O None. O Some, but less than 65.0 mmol. 65.0 mmol. More than 65.0 mmol. O None. O Some, but less than 215. mmol. ○ 215. mmol. More than 215. mmol.
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Chapter14: Chemical Equilibirum
Section: Chapter Questions
Problem 14.19QP: During an experiment with the Haber process, a researcher put 1 mol N2 and 1 mol H2 into a reaction...
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Transcribed Image Text:Nitrogen dioxide and carbon monoxide react to form nitrogen monoxide and carbon dioxide, like this:
NO₂(g) + CO (g) →→ NO(g) + CO₂(g)
-
Use this chemical equation to answer the questions in the table below.
Suppose 65.0 mmol of NO2
and
65.0 mmol of CO are added to an
empty flask. How much NO₂ will be
in the flask at equilibrium?
2
Suppose 215. mmol of NO and
215. mmol of CO₂ are added to an
empty flask. How much NO₂ will be
in the flask at equilibrium?
O None.
O Some, but less than 65.0 mmol.
65.0 mmol.
More than 65.0 mmol.
O None.
O Some, but less than 215. mmol.
○ 215. mmol.
More than 215. mmol.
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