Refer to the following equation. C6H6 (g) + 3H2 (g) C6H12 (g) When 1.00 M C6H6 and 3.00 M H2 are in a container and allowed to reach equilibrium at elevated temperature, the resulting mixture contains 0.137 M C6H6 . What is the value for Kc at this temperature? HINT: you are given an equilibrium value, and you can use it to find other equilibrium values which you need to find Kc. 7.72 x 10 -2 6.37 x 10 -2 3.05 x 10 -4 9.50 x 10 -1 2.36 x 10 4 0.658 0.792 90.7
Refer to the following equation. C6H6 (g) + 3H2 (g) C6H12 (g) When 1.00 M C6H6 and 3.00 M H2 are in a container and allowed to reach equilibrium at elevated temperature, the resulting mixture contains 0.137 M C6H6 . What is the value for Kc at this temperature? HINT: you are given an equilibrium value, and you can use it to find other equilibrium values which you need to find Kc. 7.72 x 10 -2 6.37 x 10 -2 3.05 x 10 -4 9.50 x 10 -1 2.36 x 10 4 0.658 0.792 90.7
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Refer to the following equation.
C6H6 (g) + 3H2 (g) C6H12 (g)
When 1.00 M C6H6 and 3.00 M H2 are in a container and allowed to reach equilibrium at elevated temperature, the resulting
mixture contains 0.137 M C6H6 . What is the value for Kc at this temperature?
HINT: you are given an equilibrium value, and you can use it to find other equilibrium values which you need to find Kc.
7.72 x 10 -2 |
||
6.37 x 10 -2 |
||
3.05 x 10 -4 |
||
9.50 x 10 -1 |
||
2.36 x 10 4 |
||
0.658 |
||
0.792 |
||
90.7 |
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