Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this: CH₂(g)+2H₂S(g) → 4H₂(g)+CS₂(g) - Use this chemical equation to answer the questions in the table below. Suppose 165. mmol of CH4 and 330. mmol of H₂S are added to an empty flask. How much H, will be in the flask at equilibrium? Suppose 165. mmol of H, and 41.3 mmol of CS, are added to an empty flask. How much H₂ will be in the flask at equilibrium? None. O Some, but less than 660. mmol. O 660. mmol. O More than 660. mmol. O None. Some, but less than 165. mmol. O165. mmol. More than 165. mmol. X S

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Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this:
CH₂(g)+2H₂S(g) → 4H₂(g)+CS₂(g)
Use this chemical equation to answer the questions in the table below.
Suppose 165. mmol of CH4 and
330. mmol of H₂S are added to an
empty flask. How much H₂ will be in
the flask at equilibrium?
Suppose 165. mmol of H, and
41.3 mmol of CS, are added to an
empty flask. How much H₂ will be in
the flask at equilibrium?
None.
O Some, but less than 660. mmol.
O 660. mmol.
O More than 660. mmol.
O None.
O Some, but less than 165. mmol.
O165. mmol.
More than 165. mmol.
X
S
Transcribed Image Text:Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this: CH₂(g)+2H₂S(g) → 4H₂(g)+CS₂(g) Use this chemical equation to answer the questions in the table below. Suppose 165. mmol of CH4 and 330. mmol of H₂S are added to an empty flask. How much H₂ will be in the flask at equilibrium? Suppose 165. mmol of H, and 41.3 mmol of CS, are added to an empty flask. How much H₂ will be in the flask at equilibrium? None. O Some, but less than 660. mmol. O 660. mmol. O More than 660. mmol. O None. O Some, but less than 165. mmol. O165. mmol. More than 165. mmol. X S
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