The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8-0°. The spring's length at the state 2 is L2=4 m. (2) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 2 is (two decimal places) HILAI ܪܐ 717 State 2 State 1

Elements Of Electromagnetics
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The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the
wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m.
The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the
state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls
without slipping and passes the position at the state 2 when the angle is 8-0°. The spring's
length at the state 2 is L2=4 m.
(2) If the mass center G is set as the origin (datum), the gravitational potential energy at the
state 2 is (two decimal places)
HILAI
ܪܐ
717
State 2
State 1
Transcribed Image Text:The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8-0°. The spring's length at the state 2 is L2=4 m. (2) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 2 is (two decimal places) HILAI ܪܐ 717 State 2 State 1
Expert Solution
Step 1

Write the given data.

m=20 kgr=0.6 mkG=0.4 mL0=1 mk=2 N/mL2=4 m

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