The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. (1) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 1 is___  (two decimal places) (2) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 2 is___  (two decimal places) (3) The stretched spring length of the spring at the state 1 is________(m) (two decimal places) (4) The elastic potential energy at the potion 1 is_______(N·m) (two decimal places) (5) The stretched spring length of the spring at the state 2 is _______(m) (two decimal places) (6) The elastic potential energy the state 2 is ___ (N·m ) (two decimal places) (7) The instantaneous center of zero velocity (IC) is (8) The mass moment of inertial about the mass center G is IG =_________(kg·m2 ) (two decimal places) (9) The mass moment of inertial about the IC center is IIC =_________(kg·m2 ) (two decimal places) (10) The kinetic energy at the state1?________ (N·m) (two decimal places) (11) The angular velocity at the state 2?_______(rad/s) (two decimal places) (12) The kinetic energy at the state 2?______ (N·m) (two decimal places)

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question

The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m.

(1) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 1 is___  (two decimal places)

(2) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 2 is___  (two decimal places)

(3) The stretched spring length of the spring at the state 1 is________(m) (two decimal places)

(4) The elastic potential energy at the potion 1 is_______(N·m) (two decimal places)

(5) The stretched spring length of the spring at the state 2 is _______(m) (two decimal places)

(6) The elastic potential energy the state 2 is ___ (N·m ) (two decimal places)

(7) The instantaneous center of zero velocity (IC) is

(8) The mass moment of inertial about the mass center G is I=_________(kg·m) (two decimal places)

(9) The mass moment of inertial about the IC center is IIC =_________(kg·m) (two decimal places)

(10) The kinetic energy at the state1?________ (N·m) (two decimal places)

(11) The angular velocity at the state 2?_______(rad/s) (two decimal places)

(12) The kinetic energy at the state 2?______ (N·m) (two decimal places)

 

***if you cannot solve, please submit an answer just saying why so i understand please

The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m.
The radius of gyration ke=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient
of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the
spring and the vertical direction is 0-30°. The wheel rolls without slipping and passes the position at
the state 2 when the angle is 0-0°. The spring's length at the state 2 is L₂=4 m.
(1) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 1
is_____(two decimal places)
(2) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 2
is_ _(two decimal places)
(3) The stretched spring length of the spring at the state 1 is_
(4) The elastic potential energy at the potion 1 is_
(5) The stretched spring length of the spring at the state 2 is
(6) The elastic potential energy the state 2 is
(7) The instantaneous center of zero velocity (IC) is
(8) The mass moment of inertial about the mass center G is IG=__
(9) The mass moment of inertial about the IC center is lic=_
(10) The kinetic energy at the state1?__
(11) The angular velocity at the state 2?__
(12) The kinetic energy at the state 2?___
HILLKI
L2
State 2
Li
(VG)
State 1
(m) (two decimal places)
(N-m) (two decimal places)
_(m) (two decimal places)
(Nm) (two decimal places)
_(kg-m²) (two decimal places)
(kg-m²) (two decimal places)
(Nm) (two decimal places)
(rad/s) (two decimal places)
(N-m) (two decimal places)
Transcribed Image Text:The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration ke=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 0-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 0-0°. The spring's length at the state 2 is L₂=4 m. (1) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 1 is_____(two decimal places) (2) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 2 is_ _(two decimal places) (3) The stretched spring length of the spring at the state 1 is_ (4) The elastic potential energy at the potion 1 is_ (5) The stretched spring length of the spring at the state 2 is (6) The elastic potential energy the state 2 is (7) The instantaneous center of zero velocity (IC) is (8) The mass moment of inertial about the mass center G is IG=__ (9) The mass moment of inertial about the IC center is lic=_ (10) The kinetic energy at the state1?__ (11) The angular velocity at the state 2?__ (12) The kinetic energy at the state 2?___ HILLKI L2 State 2 Li (VG) State 1 (m) (two decimal places) (N-m) (two decimal places) _(m) (two decimal places) (Nm) (two decimal places) _(kg-m²) (two decimal places) (kg-m²) (two decimal places) (Nm) (two decimal places) (rad/s) (two decimal places) (N-m) (two decimal places)
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius
of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched
length is Lo=1.0 m. The stiffness coefficient of the spring is k-2.0 N/m. The wheel is
released from rest at the state 1 when the angle between the spring and the
vertical direction is 0-30°. The wheel rolls without slipping and passes the position
at the state 2 when the angle is 0=0°. The spring's length at the state 2 is L2=4 m.
HIGH
L2
0
त
State 2
Li
State 1
Transcribed Image Text:The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k-2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 0-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 0=0°. The spring's length at the state 2 is L2=4 m. HIGH L2 0 त State 2 Li State 1
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Knowledge Booster
Design of Mechanical Springs
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY