The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration ke=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k-2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8=0°. The spring's length at the state 2 is L2=4 m. (6) The elastic potential energy the state 2 is HILAI L₂ # State 2 ZG State 1 (N-m) (two decimal places)

The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration ke=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k-2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8=0°. The spring's length at the state 2 is L2=4 m. (6) The elastic potential energy the state 2 is HILAI L₂ # State 2 ZG State 1 (N-m) (two decimal places)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A 269-lb block is released from rest when the spring is unstretched. The drum has a weight of 90 lb and a radius of gyration of ko - 0.9 ft about its center of mass O. The coefficient of stiffness of the spring is k-84 Ib/ft. The radius of the drum are: F-0.424ft and fou"0.89t. The velocity of the block after it has descended d-7 feet. Give your answer with 1 decimal.
The 3.0 kg pendulum with mass center G is pivoted at A to the ficed support CA. It has a radius of gyration of 425 mm about O-0 and swings through an amplitude 0 pendulum is in the extreme position, calculate the moments Mx, M, and M, applied by the base support to the column at C. (M, = -5.64NM, M, = 1.976NM) 60°. For the instant when the 200 mm 400 mm 500 mm
Figure shows a system of cylinder (m = 55 kg) and a load (m = 62 kg) connected through a rope. The system is released from rest and the load L moves along the inclined surface. The kinetic coefficient of friction between the load and the inclined surface is 0.22. The radius of gyration of the cylinder is 0.8 m. Take d1 = 0.5 m, d2 = 1.4 m, and a = 66°. Determine the angular velocity of the cylinder after the load L slides 1.6 m on the inclined surface. d2 d1 C The angular velocity of the cylinder is, [rad/s].
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. (8) The mass moment of inertial about the mass center G is IG =_________(kg·m2 ) (two decimal places)
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 0-0°. The spring's length at the state 2 is L2=4 m. (12) The kinetic energy at the state 2? (N-m) (two decimal places) LLLLKAL 2₂ तो State 2 Li State 1
Dynmaic i need help solving the second part
A force of P = 20 N is applied to the cable, which causes the 175-kg reel to turn without slipping on the two rollers A and B of the dispenser. Neglect the mass of the cable. Each roller can be considered as an 18-kg cylinder, having a radius of 0.1 m. The radius of gyration of the reel about its center axis is kg = 0.42 m. (Figure 1) Figure 30% 250 mm OG 500 mm A o OB 400 mm-
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 0-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8=0°. The spring's length at the state 2 is L2=4 m. (kg-m²) (two (8) The mass moment of inertial about the mass center G is IG= decimal places) HILAI L₂ State 2 State 1
The 16-kg wheel is rolling under the constant moment of M = 60 N-m. The wheel has radius r= 0.50 m, has mass center at point G, and the radius of gyration is kg = 0.23 m. The coefficients of friction between the wheel and the ground is ls = 0.28 and Uk = 0.14. If the wheel rolls without slipping, determine the angular acceleration of the wheel (in rad/s?). Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point. Take g = 9.81 m/s?. M
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration KG=0.4 m. The spring's unstretched length is Lo=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is 8-30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is 8-0°. The spring's length at the state 2 is L2=4 m. (10) The kinetic energy at the state1?__ (N-m) (two decimal places) LLLLLLL L₂ State 2 C State 1
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. Ignore the spring's mass. (5) At state 2, how long the spring is stretched from its unstretched state (length difference):________(m) (two decimal places) (6) The elastic potential energy of the spring at the state 2 is_______(N·m) (two decimal places) (7) The instantaneous center of zero velocity (IC) of the wheel at state 1 is (8) The mass moment of inertial of the wheel about its mass center G is IG =_________(kg·m2 ) (two decimal places) (9) The mass moment of inertial of the wheel about its…
The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. (1) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 1 is___ (two decimal places) (2) If the mass center G is set as the origin (datum), the gravitational potential energy at the state 2 is___ (two decimal places) (3) The stretched spring length of the spring at the state 1 is________(m) (two decimal places) (4) The elastic potential energy at the potion 1 is_______(N·m) (two decimal places) (5) The stretched spring length of the spring at the…