Many metabolites are maintained at steady-state concentrations that are far from equilibrium. A comparison of K'q and Q, the mass-action ratio, can determine whether a metabolic reaction is far from equilibrium. The equation for this equilibrium is, fructose 6-phosphate + ATP = fructose 1,6-bisphosphate + ADP Calculate Kéq for this reaction at T = 25.0 °C. AG' = -14.2 kJ/mol Kg = 1.8 x10-6 Incorrect Calculate the mass-action ratio, Q , from the approximate physiological concentrations for rat heart tissue shown in the table. Metabolite Concentration (µM) Q = 3 fructose 6-phosphate 81.0 fructose 1,6-bisphosphate 15.0 Incorrect ATP 12,500 ADP 1,340

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