Make this C language code into modular code (functions) #include #include main() { char choice; int num1, num2, result = 0; while(1) { printf("\nEnter Operator(+,-, *, /,f, s):");//f for floor division and s for square root //choice-getch(); scanf("%c",&choice); if(choice=='s'){ printf("\nEnter Value to calculate square root:"); scanf("%ld",&num1); } else{ printf("\nEnter First Value:"); scanf("%d",&num1); printf("\nEnter Second Value:"); scanf("%d",&num2); } switch (choice) { case '+': result = num1 + num2; printf("\nSum is = %d", result); break; case '-': result = num1 - num2; printf("\nDifference is =%d",result); printf("\n\nPress Enter Again for New Input\n"); break; case ***: result = num1 * num2; printf("\nProduct is = %d", result); printf("\n\nPress Enter Again for New Input\n"); break; case '/': result = num1/num2; printf("\nQuotient is = %d",result); printf("\n\nPress Enter Again for New Input\n"); break; case 'f'://floor division result = floor(num1 / num2); printf("\nResult is =%d",result); printf("\n\nPress Enter Again for New Input\n"); break; case 's': result = sqrt(num1); printf("Square root is %d", result); printf("\n\nPress Enter Again for New Input\n"); break; default: printf("\nEnter Valid Operator!!!\n"); printf("\n\nPress Enter Again for New Input\n"); } getch(); }}
Make this C language code into modular code (functions) #include #include main() { char choice; int num1, num2, result = 0; while(1) { printf("\nEnter Operator(+,-, *, /,f, s):");//f for floor division and s for square root //choice-getch(); scanf("%c",&choice); if(choice=='s'){ printf("\nEnter Value to calculate square root:"); scanf("%ld",&num1); } else{ printf("\nEnter First Value:"); scanf("%d",&num1); printf("\nEnter Second Value:"); scanf("%d",&num2); } switch (choice) { case '+': result = num1 + num2; printf("\nSum is = %d", result); break; case '-': result = num1 - num2; printf("\nDifference is =%d",result); printf("\n\nPress Enter Again for New Input\n"); break; case ***: result = num1 * num2; printf("\nProduct is = %d", result); printf("\n\nPress Enter Again for New Input\n"); break; case '/': result = num1/num2; printf("\nQuotient is = %d",result); printf("\n\nPress Enter Again for New Input\n"); break; case 'f'://floor division result = floor(num1 / num2); printf("\nResult is =%d",result); printf("\n\nPress Enter Again for New Input\n"); break; case 's': result = sqrt(num1); printf("Square root is %d", result); printf("\n\nPress Enter Again for New Input\n"); break; default: printf("\nEnter Valid Operator!!!\n"); printf("\n\nPress Enter Again for New Input\n"); } getch(); }}
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
![Make this C language code into modular code (functions) #include #include main() { char choice; int num1,
num2, result = 0; while(1) { printf("\nEnter Operator(+,-, *, /,f, s):");//f for floor division and s for square root
//choice-getch(); scanf("%c",&choice); if(choice=='s') { printf("\nEnter Value to calculate square root:");
scanf("%ld",&num1); } else{ printf("\nEnter First Value:"); scanf("%d",&num1); printf("\nEnter Second Value:");
scanf("%d",&num2); } switch (choice) { case '+': result = num1 + num2; printf("\nSum is = %d", result); break;
case '-': result = num1 - num2; printf("\nDifference is = %d", result); printf("\n\nPress Enter Again for New
Input\n"); break; case '*': result = num1 * num2; printf("\nProduct is = %d", result); printf("\n\nPress Enter
Again for New Input\n"); break; case '/': result = num1 / num2; printf("\nQuotient is = %d", result);
printf("\n\nPress Enter Again for New Input\n"); break; case 'f'://floor division result = floor(num1/num2);
printf("\nResult is = %d", result); printf("\n\nPress Enter Again for New Input\n"); break; case 's': result =
sqrt(num1); printf("Square root is %d", result); printf("\n\nPress Enter Again for New Input\n"); break; default:
printf("\nEnter Valid Operator!!!\n"); printf("\n\nPress Enter Again for New Input\n"); } getch(); } }](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F167912e8-d49a-4c5a-b074-43dc00bd2a73%2Fd2833fc1-de99-40f3-b404-b8051f18a39c%2F5emud3d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Make this C language code into modular code (functions) #include #include main() { char choice; int num1,
num2, result = 0; while(1) { printf("\nEnter Operator(+,-, *, /,f, s):");//f for floor division and s for square root
//choice-getch(); scanf("%c",&choice); if(choice=='s') { printf("\nEnter Value to calculate square root:");
scanf("%ld",&num1); } else{ printf("\nEnter First Value:"); scanf("%d",&num1); printf("\nEnter Second Value:");
scanf("%d",&num2); } switch (choice) { case '+': result = num1 + num2; printf("\nSum is = %d", result); break;
case '-': result = num1 - num2; printf("\nDifference is = %d", result); printf("\n\nPress Enter Again for New
Input\n"); break; case '*': result = num1 * num2; printf("\nProduct is = %d", result); printf("\n\nPress Enter
Again for New Input\n"); break; case '/': result = num1 / num2; printf("\nQuotient is = %d", result);
printf("\n\nPress Enter Again for New Input\n"); break; case 'f'://floor division result = floor(num1/num2);
printf("\nResult is = %d", result); printf("\n\nPress Enter Again for New Input\n"); break; case 's': result =
sqrt(num1); printf("Square root is %d", result); printf("\n\nPress Enter Again for New Input\n"); break; default:
printf("\nEnter Valid Operator!!!\n"); printf("\n\nPress Enter Again for New Input\n"); } getch(); } }
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 1 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.Recommended textbooks for you
![Database System Concepts](https://www.bartleby.com/isbn_cover_images/9780078022159/9780078022159_smallCoverImage.jpg)
Database System Concepts
Computer Science
ISBN:
9780078022159
Author:
Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:
McGraw-Hill Education
![Starting Out with Python (4th Edition)](https://www.bartleby.com/isbn_cover_images/9780134444321/9780134444321_smallCoverImage.gif)
Starting Out with Python (4th Edition)
Computer Science
ISBN:
9780134444321
Author:
Tony Gaddis
Publisher:
PEARSON
![Digital Fundamentals (11th Edition)](https://www.bartleby.com/isbn_cover_images/9780132737968/9780132737968_smallCoverImage.gif)
Digital Fundamentals (11th Edition)
Computer Science
ISBN:
9780132737968
Author:
Thomas L. Floyd
Publisher:
PEARSON
![Database System Concepts](https://www.bartleby.com/isbn_cover_images/9780078022159/9780078022159_smallCoverImage.jpg)
Database System Concepts
Computer Science
ISBN:
9780078022159
Author:
Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:
McGraw-Hill Education
![Starting Out with Python (4th Edition)](https://www.bartleby.com/isbn_cover_images/9780134444321/9780134444321_smallCoverImage.gif)
Starting Out with Python (4th Edition)
Computer Science
ISBN:
9780134444321
Author:
Tony Gaddis
Publisher:
PEARSON
![Digital Fundamentals (11th Edition)](https://www.bartleby.com/isbn_cover_images/9780132737968/9780132737968_smallCoverImage.gif)
Digital Fundamentals (11th Edition)
Computer Science
ISBN:
9780132737968
Author:
Thomas L. Floyd
Publisher:
PEARSON
![C How to Program (8th Edition)](https://www.bartleby.com/isbn_cover_images/9780133976892/9780133976892_smallCoverImage.gif)
C How to Program (8th Edition)
Computer Science
ISBN:
9780133976892
Author:
Paul J. Deitel, Harvey Deitel
Publisher:
PEARSON
![Database Systems: Design, Implementation, & Manag…](https://www.bartleby.com/isbn_cover_images/9781337627900/9781337627900_smallCoverImage.gif)
Database Systems: Design, Implementation, & Manag…
Computer Science
ISBN:
9781337627900
Author:
Carlos Coronel, Steven Morris
Publisher:
Cengage Learning
![Programmable Logic Controllers](https://www.bartleby.com/isbn_cover_images/9780073373843/9780073373843_smallCoverImage.gif)
Programmable Logic Controllers
Computer Science
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education