Let Q be the field of rational numbers and let F Q(√2, √7). You may assume that √2, √7, √14 are irrational. (a) Show that √7 Q(√2). Hence obtain that [F : Q] = 4.
Let Q be the field of rational numbers and let F Q(√2, √7). You may assume that √2, √7, √14 are irrational. (a) Show that √7 Q(√2). Hence obtain that [F : Q] = 4.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I don't understand 2 points in the solution for this problem. Can you please explain why? Thanks.
1. Why : {1, √2} is a basis for Q(√2) over Q then we conclude 2rs = 0 and r2 + 2s2 = 0 ???
2. Why: [F : Q(√2) ] = 2
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