Part 1: Solve using Cramer's rule. 2x1 + 6x2 = 26 6x1 + x₂ = -24 Part 2: Calculate the area of the parallelogram with the given vertices. (-1, -2), (3, 5), (6, 2), (10, 9) *Please show all of your work for both parts and answer correctly. Thank you.
Part 1: Solve using Cramer's rule. 2x1 + 6x2 = 26 6x1 + x₂ = -24 Part 2: Calculate the area of the parallelogram with the given vertices. (-1, -2), (3, 5), (6, 2), (10, 9) *Please show all of your work for both parts and answer correctly. Thank you.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Hello. Please answer the attached
*If you answer the question and its 2 parts correctly & show all of your work, I will give you a thumbs up. Thanks.

Transcribed Image Text:Part 1:
Solve using Cramer's rule.
2x1 + 6x₂ = 26
6x₁ + x₂ = -24
Part 2:
Calculate the area of the parallelogram
with the given vertices.
(-1, -2), (3, 5), (6, 2), (10, 9)
*Please show all of your work for both
parts and answer correctly. Thank
you.
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