The principal part of f(x) = x + x²-³√x²+x²¹ for x>0+ (with respect to y(x) = x) is: a) x + x³ b)x³ e) -24/3 d) a how I solved it, Let me know if it's correct, if not let me know why n+x²– (x³ +nª) ¹³ ⇒n+x²-x[|+ ½ x) ⇒n+2³_n-12² 2³-1² so we choose the one with the smallest degree so C.
The principal part of f(x) = x + x²-³√x²+x²¹ for x>0+ (with respect to y(x) = x) is: a) x + x³ b)x³ e) -24/3 d) a how I solved it, Let me know if it's correct, if not let me know why n+x²– (x³ +nª) ¹³ ⇒n+x²-x[|+ ½ x) ⇒n+2³_n-12² 2³-1² so we choose the one with the smallest degree so C.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Let me know if my thinking process and computations are correct and if not let me know why please
![The principal part of f(x)=x+x²-√₂²+x" for x->0+ (with respect to up(x) = x) is:
a) x + x³
b)x³
e)-4/3
d) a
how I solved it, Let me know if it's correct, if not let
me know why
2+x²³ - (x³ +2²)¹³ »n+x²-x[|+ __ x)
⇒n+2³_n-12²
⇒2³-1/²
23.
so we choose the
one with the smallest
degree
So C.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6099d21a-e15a-47f8-adbb-0c871c33581f%2F553f1898-4e90-40d5-bd92-01c2fba4ac94%2Fnc76gwh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The principal part of f(x)=x+x²-√₂²+x" for x->0+ (with respect to up(x) = x) is:
a) x + x³
b)x³
e)-4/3
d) a
how I solved it, Let me know if it's correct, if not let
me know why
2+x²³ - (x³ +2²)¹³ »n+x²-x[|+ __ x)
⇒n+2³_n-12²
⇒2³-1/²
23.
so we choose the
one with the smallest
degree
So C.
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