Left Tail Right Tail sampler = 100 Two-Tail mean = -0.0095 40 st. dev =0.050 30 20 10 0.00 null = 0 -0.20 -0.15 -0.10 -0.05 0.05 0.10 0.15 0.20 0.25 ......

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Chapter1: Starting With Matlab
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  1. Suppose you are investigating whether the proportion of milk chocolate M&M's that are green differs from the proportion of dark chocolate M&M's that are green. You purchase a bag of each variety, and summarize your data in the following table.

 

Green

Not Green

Total

 

Milk Chocolate

8

33

41

 

Dark Chocolate

4

38

42

 

Total

12

71

83

                       


(a) Define the appropriate parameter(s) and state the null and alternative hypotheses for testing if the proportion of green M&M's differs for milk chocolate and dark chocolate M&M's.






(b) Find the sample proportion of milk chocolate M&M’s that are green and the sample proportion of dark chocolate M&M’s that are green.  Then find their difference.





(c) If you were to use the following randomization distribution (based on 100 samples) to compute the p-value, what would it be?

                                

      p-value = ____________


(d) If you were to use a 5% significance level (i.e., α = 0.05), what would be your formal conclusion?




(e) Tell whether this sample provides evidence that the proportion of candies that are green differs for the two types of M&M's.  Include an assessment of the strength of your evidence (i.e., little, some, moderate, strong, or very strong).

Left Tail
Right Tail
sampler = 100
Two-Tail
mean = -0.0095
40
st. dev =0.050
30
20
10
0.00
null = 0
-0.20
-0.15
-0.10
-0.05
0.05
0.10
0.15
0.20
0.25
......
Transcribed Image Text:Left Tail Right Tail sampler = 100 Two-Tail mean = -0.0095 40 st. dev =0.050 30 20 10 0.00 null = 0 -0.20 -0.15 -0.10 -0.05 0.05 0.10 0.15 0.20 0.25 ......
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