Leaderless. The MRNA for the A repressor begins with 5'-AUG-3',5'-AUG-3', which encodes the methionine residue that begins theprotein. What is unusual about this beginning? Would it cause theMRNA to translate efficiently or not?

mRNA or messenger RNA is the molecule synthesized during the process of transcription from the DNA…

Answered: Leaderless. The MRNA for the A…

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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Similar questions

E21.
Like the lac operon, the hexose operon is controlled by a separate regulatory protein under the control of its own promoter (see the schematic of the operon below). The hexose regulatory protein is sensitive to fatty acyl CoA levels. When all hexose fuel sources are depleted, the bacteria switch to lipid metabolism and fatty acyl CoA levels increase. This turns expression of the hexose operon off. +1 +1 Regulatory Gene Pregulator Hexose Operon Genes operon regulator promoter operon promoter 5e. The regulatory protein that controls expression of the hexose operons is a transcriptional ACTIVTOR or REPRESSOR (circle one).
True or False. Rho-dependent termination of transcription in prokaryotes can take place upon the formation of a strong RNA stern loop in the MRNA just before a run of U residues. True False
4A. Write out the chemical equations (structures are not necessary) for the two steps in the reaction catalyzed by aminoacyl tRNA transferase. Include all products and reactants. Step 1: amino acid activation Step 2: aminoacyl transfer to the tRNA 4B. Write the chemical equation for the net reaction catalyzed by aminoacyl transferase. This can be determined by taking the sum of the two reactions above.
Can you explain it?
1 point Before we start the actual translation process. If we look at our transcript from sequence I, we can predict how long the polypeptide will be. 544545-33454454 Find the Open reading frame. Then tell me how many amino acids are in this poly-peptide? Provide a single integer Type your answer... A8885-349953-
GACA CAAT box A site P site E site DREASAARE III III III III III factors and RNA pol to bind to in order to activate gene expression. Accepts charged tRNA molecules whose anticodon complements the codons of mRNA. Holds a nascent elongating polypeptide before final release. Unique sequence found in bacteria between TATAAT and START. 5 upstream consensus motif that is easily melted for transcription purposes in prokaryotes.
A cluster of ribosomes. In a polysome, or polyribosome, the polypeptides associated with which ribosomes will be the longest: a. They will be the same length since the rate of translation is constant. b. Those at the 3'-end3'-end of the mRNA. c. Those at the 5'-end5'-end of the MRNA. d. Those in the middle of the mRNA.
Molecular biology, please explain in details

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Leaderless. The MRNA for the A repressor begins with 5'-AUG-3', 5'-AUG-3', which encodes the methionine residue that begins the protein. What is unusual about this beginning? Would it cause the MRNA to translate efficiently or not?