k1 For the equilibrium reaction A(g) = C(g), the following data were collected: k-1 k-1 = 2E-3 s1 k1 = 0.10 s k1 = 0.25 s1 At 298 K: At 313 K: k-1= 4E-3 s1 Calculate the equilibrium constant at 298, E,forward, Ea,reverse, and change in enthalpy for the reaction.
k1 For the equilibrium reaction A(g) = C(g), the following data were collected: k-1 k-1 = 2E-3 s1 k1 = 0.10 s k1 = 0.25 s1 At 298 K: At 313 K: k-1= 4E-3 s1 Calculate the equilibrium constant at 298, E,forward, Ea,reverse, and change in enthalpy for the reaction.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Equilibrium Reaction Analysis**
For the equilibrium reaction \( A(g) \rightleftharpoons C(g) \), the following data were collected:
**At 298 K:**
- \( k_1 = 0.10 \, \text{s}^{-1} \)
- \( k_{-1} = 2 \times 10^{-3} \, \text{s}^{-1} \)
**At 313 K:**
- \( k_1 = 0.25 \, \text{s}^{-1} \)
- \( k_{-1} = 4 \times 10^{-3} \, \text{s}^{-1} \)
**Tasks:**
Calculate the equilibrium constant at 298 K, the activation energies (\( E_{a,\text{forward}} \) and \( E_{a,\text{reverse}} \)), and the change in enthalpy for the reaction.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbf3d1070-4885-4620-8693-0f7f4a85073e%2F91ad803d-8993-49bd-9734-ef54691580cb%2F2h7uw5l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Equilibrium Reaction Analysis**
For the equilibrium reaction \( A(g) \rightleftharpoons C(g) \), the following data were collected:
**At 298 K:**
- \( k_1 = 0.10 \, \text{s}^{-1} \)
- \( k_{-1} = 2 \times 10^{-3} \, \text{s}^{-1} \)
**At 313 K:**
- \( k_1 = 0.25 \, \text{s}^{-1} \)
- \( k_{-1} = 4 \times 10^{-3} \, \text{s}^{-1} \)
**Tasks:**
Calculate the equilibrium constant at 298 K, the activation energies (\( E_{a,\text{forward}} \) and \( E_{a,\text{reverse}} \)), and the change in enthalpy for the reaction.
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