The equilibrium constant for the formation of sulfur trioxide, SO3, from sulfur dioxide, SO2, and oxygen, O 2, SO2(g) + O2(g) = SO3(g) is 2.643 \times 1012 at 298 K. The standard reaction enthalpy is -98.9 kJ mol -1. Calculate the value of the equilibrium constant at 308 K. Assume that the standard reaction enthalpy is

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Chapter17: Spontaneity, Entropy, And Free Energy
Section: Chapter Questions
Problem 112CWP: The equilibrium constant for a certain reaction increases by a factor of 6.67 when the temperature...
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The equilibrium constant for the formation of sulfur
trioxide, SO3, from sulfur dioxide, SO2, and oxygen, O
2, SO2(g) + O2(g) = SO3(g) is 2.643 \times 1012 at
298 K. The standard reaction enthalpy is -98.9 kJ mol
-1. Calculate the value of the equilibrium constant at
308 K. Assume that the standard reaction enthalpy is
constant over this temperature range.
Transcribed Image Text:The equilibrium constant for the formation of sulfur trioxide, SO3, from sulfur dioxide, SO2, and oxygen, O 2, SO2(g) + O2(g) = SO3(g) is 2.643 \times 1012 at 298 K. The standard reaction enthalpy is -98.9 kJ mol -1. Calculate the value of the equilibrium constant at 308 K. Assume that the standard reaction enthalpy is constant over this temperature range.
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