Answered: 4. Calculate the equilibrium constant…

4. Calculate the equilibrium constant for the reaction below: Nzig)t Oz(g) + Br2(g) = 2NOB (g) Kp =? Given: NO (g) + Br2 (g) = NOB (g) Kp = 5.3 N2 (g) + O2 (g) = 2 NO (g) Kp = 4.8 × 10 31 Kp =. %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Calculate AG for H,O(g)+½O¸ (g) =H,O, (g) at 600.0 K, using the following data: H2e) + O28) = Kp = 2.3 x106 at 600.0 K Kp = 1.8 x 1037 at 600.0 K H202(9) 2H2(g) + O28) = 2H20(g)
1. Cl2 (g) + CO (g) = COCI2 (g) At a temperature of 501K, the value of Ko for the reaction is 5.0. What is the value of K,? Kp = 6.1 x 105 at 25 °C 2. N2(g) + 3 H2(g) NH3(g) What is the value of K. for this reaction at 25°C?
The equilibrium system, N204(g) = 2NO2(g), has Kp = 11. For which equilibrium system is Kp = 0.091? %3D
Cc.49.
At 13.7 °C the concentration equilibrium constant K = 2.0 × 10 for a certain reaction. Here are some facts about the reaction: • C The constant pressure molar heat capacity C₁ = 2.49 J-mol K. •If the reaction is run at constant pressure, 147. kJ/mol of heat are released. •If the reaction is run at constant pressure, the volume increases by 13.%. ○ Yes. Using these facts, can you calculate K, at 3.8 °C? x10 No. If you said yes, then enter your answer at right. Round it to 2 significant digits. n If you said no, can you at least decide whether Kat 3.8 °C will be bigger or smaller than K at -13.7 °C? Yes, and K will be bigger. Yes, and K will be smaller. No. x
Calculate the value of K, for the equation C(s) + CO₂(g) given that at a certain temperature Kp = 2 CO(g) K₂ = ? C(s) + 2 H₂O(g) CO₂(g) + 2 H₂(g) H₂(g) + CO₂(g) = H₂O(g) + CO(g) Kpl = 3.35 Kp2 = 0.745
The equilibrium system shown below was analyzed and the concentrations of H2(g), I2(g) and HI(g), were found, in mol/L, to be 4.2, 3.8, 1.6 respectively. The equilibrium constant must be? H2(g) + I2(g) <=====> 2HI(g) + 65 kJ
Nitric oxide reacts with chlorine to form NOCI. 2NO(g) + Cl2g) → 2NOCI(g) The equilibrium constant K at 298K is x 107. (R = 8.314 J/K • mol) Substance: NO(g) Cl2g) NOCIG) AH°F (k]/mol) at 298 K 90.29 51.71 S°U/K• mol) at 298 K 210.65 223.0 261.60
At -8.64 °C the concentration equilibrium constant K = 7.7 for a certain reaction. Here are some facts about the reaction: -1 • The initial rate of the reaction is 5.3 mol·L¯¹·s¯¹. . If the reaction is run at constant pressure, 132. kJ/mol of heat are absorbed. • The constant pressure molar heat capacity C = 2.97 J'mol K¹. Yes. Using these facts, can you calculate K at 16. °C? x10 O No. If you said yes, then enter your answer at right. Round it to 2 significant digits. If you said no, can you at least decide whether Kat 16. °C will be bigger or smaller than K at -8.64 °C? C Yes, and K will be bigger. Yes, and K will be smaller. No.
Can you please answer question 2
At 487 K, this reaction has a Ke value of 0.0463. 2 X(g) + 3 Y(g) = 2Z(g) Calculate Kp at 487 K. Note that the pressure is in units of atmosphere (atm). Kp =
Consider the following equilibrium: 2NO₂(g) → N₂O4 (g) AG = -5.4 kJ Now suppose a reaction vessel is filled with 0.202 atm of nitrogen dioxide (NO₂) at 504. °C. A Under these conditions, will the pressure of NO₂ tend to rise or fall? Is it possible to reverse this tendency by adding N₂O4? In other words, if you said the pressure of NO₂ will tend to rise, can that be changed to a tendency to fall by adding N₂O4? Similarly, if you said the pressure of NO₂ will tend to fall, can that be changed to a tendency to rise by adding N₂O4? If you said the tendency can be reversed in the second question, calculate the minimum pressure of N₂O needed to reverse it. V Round your answer to 2 significant digits. Orise fall O yes no atm 0