Large quantities of hydrogen are needed for the synthesis of ammonia. One preparation of hydrogen involves the reaction between carbon monoxide and steam at 3.00 × 10²°C in the presence of a copper-zinc catalyst: CO(g) + H₂O(g) CO₂(g) + H₂(g) Using the standard data in the table, calculate the equilibrium constant (Kp) for the reaction at 3.00 × 102°C and the temperature at which the reaction favors the formation of CO and H₂O 0 0 Species AH (kJ/mol) s (J/mol-K) f CO(g) -110.5 H₂O(g) -241.8 CO₂(g) -393.5 H₂(g) Kp = T= 0 K 197.7 188.8 213.8 130.7
Large quantities of hydrogen are needed for the synthesis of ammonia. One preparation of hydrogen involves the reaction between carbon monoxide and steam at 3.00 × 10²°C in the presence of a copper-zinc catalyst: CO(g) + H₂O(g) CO₂(g) + H₂(g) Using the standard data in the table, calculate the equilibrium constant (Kp) for the reaction at 3.00 × 102°C and the temperature at which the reaction favors the formation of CO and H₂O 0 0 Species AH (kJ/mol) s (J/mol-K) f CO(g) -110.5 H₂O(g) -241.8 CO₂(g) -393.5 H₂(g) Kp = T= 0 K 197.7 188.8 213.8 130.7
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Large quantities of hydrogen are needed for the synthesis of ammonia. One preparation of
hydrogen involves the reaction between carbon monoxide and steam at 3.00 × 102°C in the
presence of a copper-zinc catalyst:
CO(g) + H₂O(g) CO₂(g) + H₂(g)
Using the standard data in the table, calculate the equilibrium constant (Kp) for the reaction at
3.00 × 102°C and the temperature at which the reaction favors the formation of CO and H₂O
Species ΔΗ (kJ/mol) s
f
CO(g) -110.5
H₂O(g) -241.8
CO₂(g) -393.5
H₂(g)
Kp =
T=
0
K
S¯ (J/mol·K)
197.7
188.8
213.8
130.7"
Transcribed Image Text:ces
Large quantities of hydrogen are needed for the synthesis of ammonia. One preparation of
hydrogen involves the reaction between carbon monoxide and steam at 3.00 × 102°C in the
presence of a copper-zinc catalyst:
CO(g) + H₂O(g) CO₂(g) + H₂(g)
Using the standard data in the table, calculate the equilibrium constant (Kp) for the reaction at
3.00 × 102°C and the temperature at which the reaction favors the formation of CO and H₂O
Species ΔΗ (kJ/mol) s
f
CO(g) -110.5
H₂O(g) -241.8
CO₂(g) -393.5
H₂(g)
Kp =
T=
0
K
S¯ (J/mol·K)
197.7
188.8
213.8
130.7
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