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-5 At -6.33 °C the concentration equilibrium constant K = 1.2 × 105 for a certain reaction. Here are some facts about the reaction: . If the reaction is run at constant pressure, the volume increases by 9.7%. • The net change in moles of gases is -2. • If the reaction is run at constant pressure, 126. kJ/mol of heat are absorbed. Using these facts, can you calculate Kat -26. °C? If you said yes, then enter your answer at right. Round it to 2 significant digits. If you said no, can you at least decide whether Kat -26. °C will be bigger or smaller than Kat -6:33 °C? Yes. No. Yes, and K will be bigger. Yes, and K will be smaller. No.

-5 At -6.33 °C the concentration equilibrium constant K = 1.2 × 105 for a certain reaction. Here are some facts about the reaction: . If the reaction is run at constant pressure, the volume increases by 9.7%. • The net change in moles of gases is -2. • If the reaction is run at constant pressure, 126. kJ/mol of heat are absorbed. Using these facts, can you calculate Kat -26. °C? If you said yes, then enter your answer at right. Round it to 2 significant digits. If you said no, can you at least decide whether Kat -26. °C will be bigger or smaller than Kat -6:33 °C? Yes. No. Yes, and K will be bigger. Yes, and K will be smaller. No.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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At -6.33 °C the concentration equilibrium constant K = 1.2 x 10 for a certain reaction. Here are some facts about the reaction: • If the reaction is run at constant pressure, the volume increases by 9.7%. • The net change in moles of gases is -2. • If the reaction is run at constant pressure, 126. kJ/mol of heat are absorbed. Using these facts, can you calculate Kat -26. °C? If you said yes, then enter your answer at right. Round it to 2 significant digits. If you said no, can you at least decide whether Kat –26. °℃ will be bigger or smaller than Kat -6.33 °C? Yes. O No. 0 Yes, and K will be bigger. Yes, and K will be smaller. No.
Transcribed Image Text:At -6.33 °C the concentration equilibrium constant K = 1.2 x 10 for a certain reaction. Here are some facts about the reaction: • If the reaction is run at constant pressure, the volume increases by 9.7%. • The net change in moles of gases is -2. • If the reaction is run at constant pressure, 126. kJ/mol of heat are absorbed. Using these facts, can you calculate Kat -26. °C? If you said yes, then enter your answer at right. Round it to 2 significant digits. If you said no, can you at least decide whether Kat –26. °℃ will be bigger or smaller than Kat -6.33 °C? Yes. O No. 0 Yes, and K will be bigger. Yes, and K will be smaller. No.
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Step 1

Answer:

Given data:

K1=1.2×10-5∆H=126kJ/molT1=-6.33°CT2=-26°C

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