t5n6nn 7e solve thisviewB▬▬▬6KThe probability of flu symptoms for a person not receiving any treatment is 0.028. In a clinical trial of acommon drug used to lower cholesterol, 33 of 1077 people treated experienced flu symptoms.Assuming the drug has no effect on the likelihood of flu symptoms, estimate the probability that atleast 33 people experience flu symptoms. What do these results suggest about flu symptoms as anadverse reaction to the drug?HYResumeView an example&N7(a) P(X≥ 33)= (Round to four decimal places as needed.)L*008MGet more help.To 144K9h<fiDOfCHPClear all[+(1prt scpauseCheck answerACA4) O78:44 PM10/20/2022A

Given and Probability of success p=0.028 Number of trials n=1077

Answered: K The probability of flu symptoms for a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The U.S. Department of Transportation, National Highway Traffic Safety Administration, reported that 77% of all fatally injured automobile drivers were intoxicated. A random sample of 52 records of automobile driver fatalities in a certain county showed that 33 involved an intoxicated driver. Do these data indicate that the population proportion of driver fatalities related to alcohol is less than 77% in Kit Carson County? Use ? = 0.05. (a) level of significance: .05 | H0: p = 0.77; H1: p < 0.77 (b) The standard normal, since np > 5 and nq > 5. What is the value of the sample test statistic? (Round your answer to two decimal places.) Find the P-value of the test statistic. (Round your answer to four decimal places.)
A financial analyst of Woolworths is interested in the average number of months that it takes customers to pay off their account debt. He claims that the average number of months it takes is less than four. He takes a sample of fifty customers and records the number of months it takes each customer to pay off his debt. Suppose that the test statistic value to test this claim is calculated as -0.34, determine the p-value.
A random sample of 200 female high school students in India showed that 110 are on Facebook. A separate random sample of 150 male high school students in India showed that 69 are on Facebook. Let P1 and P2 be the proportion of all female and male high school students in India, respectively, who are on Facebook. Which the following are the estimate of p(combined), pc, and the standard test statistics, z, of the difference in the population proportions? O (C) pc = 0.51, z=pc = 0.51, z=(0.55 -0.46)-51/(0.51)(0.49)200+(0.51) (0.49)150 O pc = 0.11, z-(0.11 -0.51)-0V(0.51)(0.49)200+(0.51)(0.49)150 %3D O ic - 0.51, z-(0.55 -0.46)-0V(0.51)(0.49)200+(0.51)(0.49)150 %3D O ộc = 0.51, z-(0.55-0.46)-0v(0.46)(0.54)200+(0.55)(0.45)150 O Dc = 0.51, z-(0.55 -0.46)-0v(0.55)(0.45)200+(0.46) 54)150 Next STE 165 W
When using an independent samples t-test, the author of a journal article reported that t(30) = 3.60, p < .05. Should the researcher reject the null or fail to reject the null?
Question 32 > 8% of all Americans suffer from sleep apnea. A researcher suspects that a higher percentage of those who live in the inner city have sleep apnea. Of the 385 people from the inner city surveyed, 39 of them suffered from sleep apnea. What can be concluded at the level of significance of a = 0.10? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer ✓ H₁: ? Select an answer ✓ c. The test statistic ? = d. The p-value = e. The p-value is ? ✓ a f. Based on this, we should g. Thus, the final conclusion is that ... (please enter a decimal) (Please enter a decimal) (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) Select an answer the null hypothesis. O The data suggest the population proportion is not significantly larger than 8% at a = 0.10, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is…
54% of students entering four-year colleges receive a degree within six years. Is this percent smaller for students who play intramural sports? 415 of the 800 students who played intramural sports received a degree within six years. What can be concluded at the 0.05 level of significance? H0: p = 0.54 Ha: p [ Select ] ["<", "Not Equal To", ">"] 0.54 p-Value = [ Select ] ["0.03", "0.23", "0.06", "0.11"] [ Select ] ["Fail to Reject Ho", "Reject Ho"] Conclusion: There is [ Select ] ["statistically significant", "insufficient"] evidence to make the conclusion that the population proportion of college students who play intramural sports that receive a degree within six years is less than 0.54. p-Value Interpretation: If the proportion of college students who play intramural sports that receive a degree within six yeas is equal to [ Select ] ["0.52", "0.54", "0.48", "0.50"]and if another study was done with a new randomly selected collection of…
An airline claims that the no-show rate for passengers is less than 5%. In a sample of 420 randomly selected reservations, 19 were no-shows. At =0.01, test the airlines claim.
In a sample of 47 adults randomly selected from one town, it is found that 9 of them have been exposed to a particular strain of the flu. Find the P-value for a test of the claim that the proportion of all adults in the town that have been exposed to this strain of the flu is 8%. a. 0.005 O b. 0.05 OC. 0.002 O d. 0.08
In a random sample of 1000 students, pˆ = 0.70 (or 70%) were in favor of longer hours at the school library. The standard error of pˆ (the sample proportion) is A.0.1601 B.0.0126 C.0.0145 D. 0.8000
The 2010 U.S. Census found the chance of a household being a certain size. The data is in the pmf below ("Households by age," 2013). Let X be the number (size) in a household. E(X) = k·P(X = k) 7 (or more) P(X=k) 0.267 0.336 0.158 0.137 0.063 0.024 0.015 k 1 2 3 5 6 a) The probability of a household size being more than 5, P(X > 5) = % b) In the long run, we are expected to see a household size of, E(X)= on average. Round answer to three decimal places. c) The probability that the size of a household is equal to two is %. d) The probability of a household size being three OR six is %.
A researcher rejected the null where r(56) = .050, p = .27. Was the researcher correct in rejecting the null? Group of answer choices Yes No
For a hypothesis test of the claim that the mean amount of sleep for adults is less than 9 hours, technology output shows that the hypothesis test has power of 0.4486 of supporting the claim that µ< 9 hours of sleep when the actual population mean is 7.5 hours of sleep. Interpret this value of the power, then identify the value of ß and interpret that value. Interpret this value of the power. A. The chance of recognizing that µ< 9 hours is not very high when in reality µ = 7.5 hours. B. The chance of failing to recognize that µ = 7.5 hours is not very high when in reality μ = 7.5 hours. C. The chance of recognizing that µ< 9 hours is very high when in reality μ = 7.5 hours. D. The chance of failing to recognize that μ< 9 hours is not very high when in reality μ = 7.5 hours. Identify the value of ß and interpret that value. Select the correct choice below and fill in the answer box to complete your choice. (Round to four decimal places as needed.) A. The value = indicates that there is…

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