dom sample of 200 female high school students in India ed that 110 are on Facebook. A separate random sample high school students in India showed that 69 are on Face 1 and p2 be the proportion of all female and male high sch ents in India, respectively, who are on Facebook. ch the following are the estimate of p(combined), pc, and ti dard test statistics, z, of the difference in the population ortions? C) pc 0.51, z-pc = 0.51, z=(0.55 -0.46)-51v(0.51)(0.49)200+(0.51 0.49)150 %3D %3D c = 0.11, z-(0.11-0.51)-0V(0.51)(0.49)200+(0.51)(0.49)150 %3D ộc = 0.51, z-(0.55 -0.46)-OV(0.51)(0.49)200+(0.51)(0.49)150 %3D ộc = 0.51, z-(0.55-0.46)-0v(0.46)(0.54)200+(0.55)(0.45)150 %3D pc = 0.51, z=(0.55-0.46)-0v(0.55)(0.45)200+(0.46)/0.54)150 %3D
dom sample of 200 female high school students in India ed that 110 are on Facebook. A separate random sample high school students in India showed that 69 are on Face 1 and p2 be the proportion of all female and male high sch ents in India, respectively, who are on Facebook. ch the following are the estimate of p(combined), pc, and ti dard test statistics, z, of the difference in the population ortions? C) pc 0.51, z-pc = 0.51, z=(0.55 -0.46)-51v(0.51)(0.49)200+(0.51 0.49)150 %3D %3D c = 0.11, z-(0.11-0.51)-0V(0.51)(0.49)200+(0.51)(0.49)150 %3D ộc = 0.51, z-(0.55 -0.46)-OV(0.51)(0.49)200+(0.51)(0.49)150 %3D ộc = 0.51, z-(0.55-0.46)-0v(0.46)(0.54)200+(0.55)(0.45)150 %3D pc = 0.51, z=(0.55-0.46)-0v(0.55)(0.45)200+(0.46)/0.54)150 %3D
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 1GP
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Question
Transcribed Image Text:A random sample of 200 female high school students in India
showed that 110 are on Facebook. A separate random sample of 150
male high school students in India showed that 69 are on Facebook.
Let
P1
and
P2
be the proportion of all female and male high school
students in India, respectively, who are on Facebook.
Which the following are the estimate of p(combined), pc, and the
standard test statistics, z, of the difference in the population
proportions?
O (C) pc = 0.51, z=pc = 0.51, z=(0.55 -0.46)-51/(0.51)(0.49)200+(0.51)
(0.49)150
O pc = 0.11, z-(0.11 -0.51)-0V(0.51)(0.49)200+(0.51)(0.49)150
%3D
O ic - 0.51, z-(0.55 -0.46)-0V(0.51)(0.49)200+(0.51)(0.49)150
%3D
O ộc = 0.51, z-(0.55-0.46)-0v(0.46)(0.54)200+(0.55)(0.45)150
O Dc = 0.51, z-(0.55 -0.46)-0v(0.55)(0.45)200+(0.46) 54)150
Next
STE
165
W
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