Next questionWhen a man observed a sobriety checkpoint conducted by a police department, he saw 692 drivers were screened and 9 were arrested for driving while intoxicated.Based on those results, we can estimate that P(W)=0.01301, where W denotes the event of screening a driver and getting someone who is intoxicated. What doesP(W) denote, and what is its value?burcescesspe her?What does P (W) represent?OA. P (W) denotes the probability of a driver passing through the sobriety checkpoint.OB. P (W) denotes the probability of screening a driver and finding that he or she is intoxicated.OC. P (W) denotes the probability of screening a driver and finding that he or she is not intoxicated.OD. P(W) denotes the probability of driver being intoxicated.2P(W) =(Round to five decimal places as needed.)@>2WSX#11:59pm3E$D4RPJLCFBi%5T6BS&………Ha7#hpUN8J1(M9KN411>PoO.L(?P:86°F{ADD40)+rNext?=YSp1prt scctribackspace1pause6:13 PM6/30/2022seseeS

Given: n = 692 X = 9 P(W) = 0.01301 Formula Used: P(W) = 1-P(W)

Answered: Next question When a man observed a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The following equations were estimated using the data in ECONMATH, with standard errors reported under coefficients. The average class score, measured as a percentage, is about 72.2; exactly 50% of the students are male; and the average of colgpa (grade point average at the start of the term) is about 2.81. score = 32.31 + 14.32 colgpa (2.00) (0.70) n = 856, R² = .329, R = .328. 29.66 + 3.83 male + 14.57 colgpa score = (2.04) (0.74) (0.69) n = 856, R? = .349, R = .348.
For each p value stated below (1) what is the decision for each if α=.05 and (2) what is the decision for each if α=.01? (a) p=.1000 (b)p=.0050
A golf club manufacturer claims that golfers can lower their scores by using the manufacturer's newly designed golf clubs. Eight golfers are randomly selected and each is asked to give his or her most recent score. After using the new clubs for one month, the golfers are asked again to give their most recent score. The scores for each golfer are given in the table below. Is there enough evidence to support the manufacturer's claim? Let d=(golf score after using the newly designed golf clubs)−(golf score before using the newly designed golf clubs)d=(golf score after using the newly designed golf clubs)−(golf score before using the newly designed golf clubs). Use a significance level of α=0.01 for the test. Assume that the scores are normally distributed for the population of golfers both before and after using the newly designed clubs. Golfer 1 2 3 4 5 6 7 8 Score (old design) 94 89 87 88 86 90 86 94 Score (new design) 87 95 85 83 88 86 84 88 Step 2 of 5 : Find the value…
if the results of a study using the chi-square tests are summarized as x2 ( 1,N=360) = 10.00,p<.01,then you would know that it was a what study?
Q2.1 Hypotheses In a clinical trial to compare the effectiveness of two drugs in preventing heart attacks, 25,620 patients were randomly divided into three groups. One group took a tablet of drug A each day. The next group took a table of drug B each day. The third group took one table of each drug each day. Patients were studied for 56 months and the number of who suffered heart attacks (fatal and non-fatal) were counted. Write the appropriate hypotheses to test if there would be an association between these treatments and cardiac outcome. Save Answer Q2.2 Conditions Values in the table represent counts, (expected values), and [Chi-square components] for this study. Drug A Drug B Both drugs Save Answer Is the sample size of 25,620 large enough? Explain how you know. Q2.3 Mechanics Fatal Heart Attack 598 (607.14) [0.1376] 603 (609.56) [0.0706] 620 (604.30) [0.4079] Drug A Drug B Both drugs Values in the table represent counts, (expected values), and [Chi-square components] for this…
7.16 Using an app or the Web on a smartphone. The Nielsen Company reports that U.S. residents aged 18 to 34 years spend an average of 2.83 hours per day using an app or the Web on a smartphones You wonder if this it true for students at your large university because you rarely see students not using their smartphones. You collect an SRS of n = 75 students and obtain 2 = 3.17 hours with s =1.36 hours. (a) Report the 95% confidence interval for u, the average number of hours per month that students at your university use the Internet on a computer. (b) Use this interval to test whether the average time for students at your university is different from the average, reported by Nielsen. Use the 5% significance level. Summarize your results.
We want to assess the relationship between class rank and how many minutes a person spends on social media. We randomly select 5 students from UMD and have them report their class rank and number of minutes per week they spend on social media. We get the following data. Because class rank is ordinal data, we want to compute Spearman's rho. Please compute the numerator for Spearman's rho and use 4 decimal places for all computations and final answer. (the numerator is referring to the numerator of the fraction, not including the 1- part) Minutes on Social Class Rank Media per Week 100 1,302 500 25 250 10 600 50 200
There are 150,000 households in Market City. A local phone repair shop takes a random sample of 50 households and finds that the average number of phones per household from the sample last year that needed to be repaired was 1.05 ± 0.23. Which of the following is an estimate of the total number of phones that needed repairing last year in Market City? O Between 82 and 128 phones O Between 123,000 and 192,000 phones Between 105 and 23 phones O Between 157,500 and 34,500 phones.
Suppose P(A) = 0.59, P(B) = 0.28, and P(An B)= 0.01. What is P(Aª|B)? [Give your numeric response to at least 3 decimal places. Give only the number, and no extra characters or symbols.]
A study of n = 2252 adults age 18 or older found that 72% of the cell phone users send and receive text messages.15 A study of n = 800 teens age 12 to 17 found that 87% of the teen cell phone users send and receive text messages. What is the best estimate for the difference in the proportion of cell phone users who use text messages, between adults (defined as 18 and over) and teens? Give notation (as a difference with a minus sign) for the quantity we are trying to estimate, notation for the quantity that gives the best estimate, and the value of the best estimate. Be sure to clearly define any parameters in the context of this situation.
A golf club manufacturer claims that golfers can lower their scores by using the manufacturer's newly designed golf clubs. Eight golfers are randomly selected and each is asked to give his or her most recent score. After using the new clubs for one month, the golfers are asked again to give their most recent score. The scores for each golfer are given in the table below. Is there enough evidence to support the manufacturer's claim? Let d=(golf score after using the newly designed golf clubs)−(golf score before using the newly designed golf clubs)d=(golf score after using the newly designed golf clubs)−(golf score before using the newly designed golf clubs). Use a significance level of α=0.05 for the test. Assume that the scores are normally distributed for the population of golfers both before and after using the newly designed clubs. Golfer 1 2 3 4 5 6 7 8 Score (old design) 93 86 84 96 89 81 92 94 Score (new design) 91 90 80 92 91 77 89 87 Step 1 of 5:State the null and…
A B This graph has an r of -0.5. C D

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