K The data to the right represent the number of customers waiting for a table at 6:00 P.M. for 40 consecutive Saturdays at Bobak's Restaurant. Complete parts (a) through (h) below. (b) Construct a frequency distribution of the data. Number of Customers 1-3 4-6 7-9 10-12 13-15 (c) Construct a relative frequency distribution of the data. Number of Relative Frequency Customers 1-3 4-6 7-9 (a) Are these data discrete or continuous? Explain. O A. The data are discrete because it was recorded for 40 consecutive Saturdays. OB. The data are continuous because it was recorded for 40 consecutive Saturdays. OC. The data are discrete because there are a finite or countable number of values. OD. The data are continuous because there are a finite or countable number of values. Frequency Frequency A. Relative Frequency 1852963O 10-12 13-15 (Type integers or decimals. Do not round.) (d) What percentage of the Saturdays had 7 or more customers waiting for a table at 6:00 P.M.? (Type an integer or a decimal. Do not round.) (f) Construct a frequency histogram of the data. Choose the correct histogram below. % (Type an integer or a decimal. Do not round.) (e) What percentage of the Saturdays had 9 or fewer customers waiting for a table at 6:00 P.M.? 1 4 7 10 13 16 Number of Customers 0.6+ 0.5- 0.4 0.3- 0.24 0.1- 0- 14 7 10 13 16 Number of Customers B. G Frequency T852963 B. Relative Frequency 0.6- 0.54 0.4 0.3- 0.2 0.1- Frequency 1 4 7 10 13 16 Number of Customers (g) Construct a relative frequency histogram of the data. Choose the correct histogram below. O A. 14 7 10 13 16 Number of Customers 5 13 7 13 6 O 1852963O C. Relative Frequency 9 8 11 6 11 8 8 6 2 3 oooooo 65432TO 4 7 10 13 16 Number of Customers Hilllll 5 7 2 3 6 L 9 3 5 6 3 4 7 10 13 16 Number of Customers (h) Describe the shape of the distribution. Choose the correct answer below. Frequency 4 7 4 5 7 D. Relative Frequency TRENDEMO 65432TO 4 3 4 7 10 13 16 Number of Customers 0.6+ SOPEL 4 7 10 13 16 Number of Customers O A. The distribution is skewed left because the left tail is longer than the right tail. OB. The distribution is skewed left because the right tail is longer than the left tail. OC. The distribution is symmetric because the left and right sides are approximately mirror images. OD. The distribution is skewed right because the left tail is longer than the right tail. O E. The distribution is symmetric because the bars in the histograms are all approximately the same height. OF. The distribution is skewed right because the right tail is longer than the left tail.

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K
11:41
The data to the right represent the number of
customers waiting for a table at 6:00 P.M. for 40
consecutive Saturdays at Bobak's Restaurant.
Complete parts (a) through (h) below.
(b) Construct a frequency distribution of the data.
Number of
Customers
1-3
4-6
7-9
10-12
13-15
(c) Construct a relative frequency distribution of the data.
Number of
Relative
Frequency
Customers
1-3
4-6
7-9
(a) Are these data discrete or continuous? Explain.
O A. The data are discrete because it was recorded for 40 consecutive Saturdays.
OB. The data are continuous because it was recorded for 40 consecutive Saturdays.
OC. The data are discrete because there are a finite or countable number of values.
O D. The data are continuous because there are a finite or countable number of values.
O A.
Frequency
2111
-லமNகமிறம்
Frequency
10-12
13-15
(Type integers or decimals. Do not round.)
(d) What percentage of the Saturdays had 7 or more customers waiting for a table at 6:00 P.M.?
A.
Relative Frequency
(Type an integer or a decimal. Do not round.)
(e) What percentage of the Saturdays had 9 or fewer customers waiting for a table at 6:00 P.M.?
(Type an integer or a decimal. Do not round.)
(f) Construct a frequency histogram of the data. Choose the correct histogram below.
4 7 10 13 16
Number of Customers
☐☐☐☐
0.6+
0.5-
0.41
0.3-
0.2-1
0.1-
01
4 7 10 13 16
Number of Customers
Frequency
|||
=
B.
Relative Frequency
1852963
4 7 10 13 16
Number of Customers
B.
(g) Construct a relative frequency histogram of the data. Choose the correct histogram below.
0.6+
0.5-
0.41
0.3-
0.24
0.1
01
5
13
7
11
13
11 8
6 8 6
4 7 10 13 16
Number of Customers.
Frequency
Relative Frequency
பழமய மறம்
O
9
8
<!!!!!!!
LTE2
2
5
3
7
6 2
3
6
4 7 10 13 16
Number of Customers
P7NWAGO
0.54
0.3-
0.2-
0.1-
0-
(h) Describe the shape of the distribution. Choose the correct answer below.
9 4
3
7
5
4
6
5
3
7
7 10 13 16
Number of Customers
Frequency
Relative Frequency
185296MO
D.
4
3
4
7
7
0.6-
0.5-
0.44
0.3-
0.2
0.1
0-
O A. The distribution is skewed left because the left tail is longer than the right tail.
OB. The distribution is skewed left because the right tail is longer than the left tail.
C. The distribution is symmetric because the left and right sides are approximately mirror images.
OD. The distribution is skewed right because the left tail is longer than the right tail.
48%
7 10 13 16
Number of Customers.
30
8
6
11
4
O E. The distribution is symmetric because the bars in the histograms are all approximately the same height.
OF. The distribution is skewed right because the right tail is longer than the left tail.
4 7 10 13 16
Number of Customers
Transcribed Image Text:K 11:41 The data to the right represent the number of customers waiting for a table at 6:00 P.M. for 40 consecutive Saturdays at Bobak's Restaurant. Complete parts (a) through (h) below. (b) Construct a frequency distribution of the data. Number of Customers 1-3 4-6 7-9 10-12 13-15 (c) Construct a relative frequency distribution of the data. Number of Relative Frequency Customers 1-3 4-6 7-9 (a) Are these data discrete or continuous? Explain. O A. The data are discrete because it was recorded for 40 consecutive Saturdays. OB. The data are continuous because it was recorded for 40 consecutive Saturdays. OC. The data are discrete because there are a finite or countable number of values. O D. The data are continuous because there are a finite or countable number of values. O A. Frequency 2111 -லமNகமிறம் Frequency 10-12 13-15 (Type integers or decimals. Do not round.) (d) What percentage of the Saturdays had 7 or more customers waiting for a table at 6:00 P.M.? A. Relative Frequency (Type an integer or a decimal. Do not round.) (e) What percentage of the Saturdays had 9 or fewer customers waiting for a table at 6:00 P.M.? (Type an integer or a decimal. Do not round.) (f) Construct a frequency histogram of the data. Choose the correct histogram below. 4 7 10 13 16 Number of Customers ☐☐☐☐ 0.6+ 0.5- 0.41 0.3- 0.2-1 0.1- 01 4 7 10 13 16 Number of Customers Frequency ||| = B. Relative Frequency 1852963 4 7 10 13 16 Number of Customers B. (g) Construct a relative frequency histogram of the data. Choose the correct histogram below. 0.6+ 0.5- 0.41 0.3- 0.24 0.1 01 5 13 7 11 13 11 8 6 8 6 4 7 10 13 16 Number of Customers. Frequency Relative Frequency பழமய மறம் O 9 8 <!!!!!!! LTE2 2 5 3 7 6 2 3 6 4 7 10 13 16 Number of Customers P7NWAGO 0.54 0.3- 0.2- 0.1- 0- (h) Describe the shape of the distribution. Choose the correct answer below. 9 4 3 7 5 4 6 5 3 7 7 10 13 16 Number of Customers Frequency Relative Frequency 185296MO D. 4 3 4 7 7 0.6- 0.5- 0.44 0.3- 0.2 0.1 0- O A. The distribution is skewed left because the left tail is longer than the right tail. OB. The distribution is skewed left because the right tail is longer than the left tail. C. The distribution is symmetric because the left and right sides are approximately mirror images. OD. The distribution is skewed right because the left tail is longer than the right tail. 48% 7 10 13 16 Number of Customers. 30 8 6 11 4 O E. The distribution is symmetric because the bars in the histograms are all approximately the same height. OF. The distribution is skewed right because the right tail is longer than the left tail. 4 7 10 13 16 Number of Customers
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