(a) Are these data discrete or continuous? Explain. O A. The data are discrete because it was recorded for 40 consecutive Saturdays. B. The data are continuous because it was recorded for 40 consecutive Saturdays. OC. The data are discrete because there are a finite or countable number of values. OD. The data are continuous because there are a finite or countable number of values. (b) Construct a frequency distribution of the data. Number of Customers 1-3 4-6 7-9 10-12 13-15 Frequency (c) Construct a relative frequency distribution of the data. Number of Customers 1-3 4-6 7-9 10-12 13-15 (Type integers or decimals. Do not round.) Relative Frequency

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3:58
K
The data to the right represent the number of
customers waiting for a table at 6:00 P.M. for 40
consecutive Saturdays at Bobak's Restaurant.
Complete parts (a) through (h) below.
(b) Construct a frequency distribution of the data.
Number of
Customers
1-3
4-6
7-9
10-12
13-15
(c) Construct a relative frequency distribution of the data.
Number of
Customers
1-3
4-6
7-9
O A.
Frequency
(a) Are these data discrete or continuous? Explain.
O A. The data are discrete because it was recorded for 40 consecutive Saturdays.
OB. The data are continuous because it was recorded for 40 consecutive Saturdays.
OC. The data are discrete because there are a finite or countable number of values.
O D. The data are continuous because there are a finite or countable number of values.
20129
Frequency
O A.
Relative Frequency
Relative
Frequency
7 10 13 16
Number of Customers
0.6+
0.5+
0.4+
0.3-
0.2
0.1-
0-
☐☐
10-12
13-15
(Type integers or decimals. Do not round.)
(d) What percentage of the Saturdays had 4 or more customers waiting for a table at 6:00 P.M.?
%
(Type an integer or a decimal. Do not round.)
(f) Construct a frequency histogram of the data. Choose the correct histogram below.
%
(Type an integer or a decimal. Do not round.)
(e) What percentage of the Saturdays had 6 or fewer customers waiting for a table at 6:00 P.M.?
4 7 10 13 16
Number of Customers
|||
=
Frequency
Q
B.
21+
18-
L852963o
Relative Frequency
B.
4 7 10 13 16
Number of Customers
0.6+
0.5+
0.4+
0.3-
0.2-
0.1-
0-4
(g) Construct a relative frequency histogram of the data. Choose the correct histogram below.
1 4 7 10 13 16
Number of Customers
7
13
8
9
13
12
5 10 4 7
Frequency
8
Vol 4G. 31%
LTE2
10
NOENDEMO
Relative Frequency
O
4
5
0.6+
0.5
0.4-
0.3
0.2
0.1-
0
5
7
2
2
(h) Describe the shape of the distribution. Choose the correct answer below.
4 7 10 13 16
Number of Customers
8
3
6
7
4
4 7 10 13 16
Number of Customers
Frequency
5
7
5
3
6
) D.
Relative Frequency
0.6+
*****
4 7 10 13 16
Number of Customers
5-
Spger
0.1-
4
3
5
OA. The distribution is skewed right because the right tail is longer than the left tail.
OB. The distribution is skewed left because the right tail is longer than the left tail.
OC. The distribution is symmetric because the bars in the histograms are all approximately the same height.
O D. The distribution is symmetric because the left and right sides are approximately mirror images.
O E. The distribution is skewed left because the left tail is longer than the right tail.
OF. The distribution is skewed right because the left tail is longer than the right tail.
4 7 10 13 16
Number of Customers
O
Q
G
Transcribed Image Text:3:58 K The data to the right represent the number of customers waiting for a table at 6:00 P.M. for 40 consecutive Saturdays at Bobak's Restaurant. Complete parts (a) through (h) below. (b) Construct a frequency distribution of the data. Number of Customers 1-3 4-6 7-9 10-12 13-15 (c) Construct a relative frequency distribution of the data. Number of Customers 1-3 4-6 7-9 O A. Frequency (a) Are these data discrete or continuous? Explain. O A. The data are discrete because it was recorded for 40 consecutive Saturdays. OB. The data are continuous because it was recorded for 40 consecutive Saturdays. OC. The data are discrete because there are a finite or countable number of values. O D. The data are continuous because there are a finite or countable number of values. 20129 Frequency O A. Relative Frequency Relative Frequency 7 10 13 16 Number of Customers 0.6+ 0.5+ 0.4+ 0.3- 0.2 0.1- 0- ☐☐ 10-12 13-15 (Type integers or decimals. Do not round.) (d) What percentage of the Saturdays had 4 or more customers waiting for a table at 6:00 P.M.? % (Type an integer or a decimal. Do not round.) (f) Construct a frequency histogram of the data. Choose the correct histogram below. % (Type an integer or a decimal. Do not round.) (e) What percentage of the Saturdays had 6 or fewer customers waiting for a table at 6:00 P.M.? 4 7 10 13 16 Number of Customers ||| = Frequency Q B. 21+ 18- L852963o Relative Frequency B. 4 7 10 13 16 Number of Customers 0.6+ 0.5+ 0.4+ 0.3- 0.2- 0.1- 0-4 (g) Construct a relative frequency histogram of the data. Choose the correct histogram below. 1 4 7 10 13 16 Number of Customers 7 13 8 9 13 12 5 10 4 7 Frequency 8 Vol 4G. 31% LTE2 10 NOENDEMO Relative Frequency O 4 5 0.6+ 0.5 0.4- 0.3 0.2 0.1- 0 5 7 2 2 (h) Describe the shape of the distribution. Choose the correct answer below. 4 7 10 13 16 Number of Customers 8 3 6 7 4 4 7 10 13 16 Number of Customers Frequency 5 7 5 3 6 ) D. Relative Frequency 0.6+ ***** 4 7 10 13 16 Number of Customers 5- Spger 0.1- 4 3 5 OA. The distribution is skewed right because the right tail is longer than the left tail. OB. The distribution is skewed left because the right tail is longer than the left tail. OC. The distribution is symmetric because the bars in the histograms are all approximately the same height. O D. The distribution is symmetric because the left and right sides are approximately mirror images. O E. The distribution is skewed left because the left tail is longer than the right tail. OF. The distribution is skewed right because the left tail is longer than the right tail. 4 7 10 13 16 Number of Customers O Q G
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