Is my work correct?Question: What is the percent yeild of the nicke(II) coordination?[Ni(H2O)6]Cl2 used = 6.140 g[Ni(en)3]Cl2 produced = 7.001 gWorkmol of [Ni(H2O)6]Cl26.140 g/237.67 g/mol = 0.0258 mol [Ni(H2O)6]Cl2mol of [Ni(en)3]Cl20.0258 mol [Ni(H2O)6]Cl2 x (1 mol [Ni(H2O)6]Cl2/1mol [Ni(en)3]Cl2) = 0.0258 molgrams of [Ni(en)3]Cl20.0258 mol x 309.89 g/mol = 8.00 g% yield 7.001 g/8.00 g = 87.5%

The number of moles for a given chemical species refers to the ratio of mass of the species to that…

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question: What is the percent yeild of the nicke(II) coordination?

[Ni(H₂O)₆]Cl₂ used = 6.140 g
[Ni(en)₃]Cl₂ produced = 7.001 g

Work

mol of [Ni(H₂O)₆]Cl₂
- 6.140 g/237.67 g/mol = 0.0258 mol [Ni(H₂O)₆]Cl₂
mol of [Ni(en)₃]Cl₂
- 0.0258 mol [Ni(H₂O)₆]Cl₂x (1 mol [Ni(H₂O)₆]Cl₂/1mol [Ni(en)₃]Cl₂) = 0.0258 mol
grams of [Ni(en)₃]Cl₂
- 0.0258 mol x 309.89 g/mol = 8.00 g
% yield
- 7.001 g/8.00 g = 87.5%

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