synthesis of Tris(ethylenediamine)nickel(II) chloride dihydrate The equations of the preparation of [Ni(en)3]CI2·2H2O are written: [Ni(H2O)6]Cl2 + 3 en → [Ni(en)3]Cl2·2H2O + 4 H2O Where en = H2N-CH2-CH2–NH2 For experiment used: 6g of NiCl2-6H20 in 50 ml of H2O. - 20 ml of ethylenediamine. - Heat the solution until the solution volume becomes 25mL. - add two drops of ethylenediamine. - Collect the product on a Büchner funnel and wash it with two 5 ml of ethanol. Note: I collected 9.518 grams of Tris(ethylenediamine)nickel(II) chloride dihydrate at the end of this experiment. Experimental Calculations: 1- Theoretical weight of the precipitate = Molecular weight of the product X Weight of the reacted substance Molecular weight of the reacted substanc 2- Experimental weight of the precipitate = 9.518 g Experimental weight of the precipitat Theoretical weight of the precipitat 3- Yield of the reaction = X100 = 4- Percentage weight of each element = Atomic eight of the elements X no of its atom ×100 = Molecular weight of the comple
synthesis of Tris(ethylenediamine)nickel(II) chloride dihydrate The equations of the preparation of [Ni(en)3]CI2·2H2O are written: [Ni(H2O)6]Cl2 + 3 en → [Ni(en)3]Cl2·2H2O + 4 H2O Where en = H2N-CH2-CH2–NH2 For experiment used: 6g of NiCl2-6H20 in 50 ml of H2O. - 20 ml of ethylenediamine. - Heat the solution until the solution volume becomes 25mL. - add two drops of ethylenediamine. - Collect the product on a Büchner funnel and wash it with two 5 ml of ethanol. Note: I collected 9.518 grams of Tris(ethylenediamine)nickel(II) chloride dihydrate at the end of this experiment. Experimental Calculations: 1- Theoretical weight of the precipitate = Molecular weight of the product X Weight of the reacted substance Molecular weight of the reacted substanc 2- Experimental weight of the precipitate = 9.518 g Experimental weight of the precipitat Theoretical weight of the precipitat 3- Yield of the reaction = X100 = 4- Percentage weight of each element = Atomic eight of the elements X no of its atom ×100 = Molecular weight of the comple
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Experimental calculations!
![synthesis of Tris(ethylenediamine)nickel(1I) chloride dihydrate
The equations of the preparation of [Ni(en)3]C|2·2H2O are written:
[Ni(H2O)6]Cl2 + 3 en → [Ni(en)3]Cl2:2H2O + 4 H2O
Where en = H2N–CH2-CH2–NH2
For experiment used:
- 6g of NiCl2-6H20 in 50 mL of H20.
- 20 ml of ethylenediamine.
- Heat the solution until the solution volume becomes 25mL.
- add two drops of ethylenediamine.
- Collect the product on a Büchner funnel and wash it with two 5 mL of
ethanol.
Note: I collected 9.518 grams of Tris(ethylenediamine)nickel(1I) chloride
dihydrate at the end of this experiment.
Experimental Calculations:
1- Theoretical weight of the precipitate =
Molecular weight of the product X Weight of the reacted substance
Molecular weight of the reacted substanc
2- Experimental weight of the precipitate = 9.518 g
Experimental weight of the precipitat
Theoretical weight of the precipitat
3- Yield of the reaction =
X100 =
4- Percentage weight of each element =
Atomic eight of the elements X no of its atom
x100 =
Molecular weight of the comple](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd7e684e8-1e0a-4f8a-956e-6ea8d96f3386%2F0e158300-c07f-458c-b1ac-7cdf1c410219%2Fzz1nsro_processed.jpeg&w=3840&q=75)
Transcribed Image Text:synthesis of Tris(ethylenediamine)nickel(1I) chloride dihydrate
The equations of the preparation of [Ni(en)3]C|2·2H2O are written:
[Ni(H2O)6]Cl2 + 3 en → [Ni(en)3]Cl2:2H2O + 4 H2O
Where en = H2N–CH2-CH2–NH2
For experiment used:
- 6g of NiCl2-6H20 in 50 mL of H20.
- 20 ml of ethylenediamine.
- Heat the solution until the solution volume becomes 25mL.
- add two drops of ethylenediamine.
- Collect the product on a Büchner funnel and wash it with two 5 mL of
ethanol.
Note: I collected 9.518 grams of Tris(ethylenediamine)nickel(1I) chloride
dihydrate at the end of this experiment.
Experimental Calculations:
1- Theoretical weight of the precipitate =
Molecular weight of the product X Weight of the reacted substance
Molecular weight of the reacted substanc
2- Experimental weight of the precipitate = 9.518 g
Experimental weight of the precipitat
Theoretical weight of the precipitat
3- Yield of the reaction =
X100 =
4- Percentage weight of each element =
Atomic eight of the elements X no of its atom
x100 =
Molecular weight of the comple
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