Interpret computer output: A sample of college students was asked whether they had a job outside of school. Thefollowing MINITAB output presents the results of a hypothesis test regarding the proportion of college students who have ajob outside of school.Test of p=0.3 vs p>0.395%LowerX NSample pBoundZ-ValueP-Value411 11980.343072 0.3205113.250.001Part: 0 / 3Part 1 of 3(a) What are the null and alternate hypotheses?Ho:OOD=0H:

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Answered: Interpret computer output: A sample of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
We compute a sample correlation coefficient of r=0.692 from a set of 12 data pairs. We are testing Ho:p=0 against H;:p#0 at a = 0.05. The value of the test statistic for this test is: O 3.18 O 3.64 O 3.03 3.94
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.16, y = 102.3, r= 0.810, P-value = 0.000, and y = 23.09+0.78x, where x represents the IQ score of the wife. Find the best %3D %3D %3D predicted value of y given that the wife has an IQ of 109? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. .... The best predicted value of y is . (Round to two decimal places as needed.) Critical values of the pearson correlation coefficient r NOTE: To test Ho: p = 0 against H,: p#0, reject Ho |if the absolute value of r is greater than the critical value in the table. a = 0.05 a = 0.01 4 0.950 0.990 0.878 0.959 0.811 0.917 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0.361 0.463 35 0.335 0.430 40…
2
(Non Parametric Test) Following are the weight gains in pounds of 2 randomly samples of young turkeys fed 2 different diets: Diet 1: 16.3, 10.1, 10.7, 13.5, 14.9, 11.8, 14.3, 10.2, 12.0, 14.7, 23.6, 15.1, 14.5, 18.4, 13.2 & 14.0 Diet 2: 21.3, 23.8, 15.4, 19.6, 12.0, 13.9, 18.8, 19.2, 15.3, 20.1, 14.8, 18.9, 20.7, 21.1, 15.8, & 16.2 Test @ 0.01 level of significance to test Ho that the 2 population sampled are identical against HA that on the average the second diet produces a greater gain in weight.
The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:
An experiment was run to determine whether four specific fire temperatures affect the density of acertain type of brick. A completely randomized experiment led to the following data: Temperature Density 100 21.8 21.9 21.7 21.6 21.7 125 21.7 21.4 21.5 21.4 150 21.9 21.8 21.8 21.6 21.5 175 21.9 21.7 21.8 21.4 Is it appropriate to compare the means using the Fisher LSD method (for example) in this experiment?
The following data represent a sample of people's smoking habits and their usage of seat belts while in a car. A researcher wants to determine whether smoking habits and seat belt usage are related. Test the researcher's claim at the a = 0.05 level of significance. No Seat Belt Seat Belt Smoke 67 448 Do not Smoke 327 2,187 *Source: Harris Poll a. Determine the null and alternative hypotheses. O Ho: Smoking habits and seat belt usage have the same distribution. Ha: Smoking habits and seat belt usage follow a different distribution. O Ho: Smoking habits and seat belt usage are independent. Ha: Smoking habits and seat belt usage are dependent. b. Determine the test Statistic. Round to two decimal places. c. Determine the p-value. Round to four decimal places. p-value = d. Make a decision. Reject the null hypothesis. O Fail to reject the null hypothesis. e. Make a conclusion. O There is not sufficient evidence to support the claim that smoking habits and seat belt usage are related. O…
The following information is available for two samples selected from independent normally distributed populations. Complete parts (a) and (b). s? = 57.3 s2 = 20.6 Population A: n= 13 Population B: n= 21 a. At the 0.05 level of significance, is there evidence of a difference between of and o3? Determine the hypotheses. Choose the correct answer below. O A. Ho of = 03 O B. Ho, o7 so? O D. Ho; o7 +o3 OC. Họ; o7 203 H,: of o?? What is your statistical decision? The upper-tail critical value of F is (Round to two decimal places as needed.) What is your statistical decision? V Ho. There is V evidence that o? >o3.
Which combination would lead you to Fail to Reject H0? ANOVA: Fobt = 3.61 Fcrit = 2.55 2-tailed t-test: tobt = 2.36 tcrit = 1.89 Correlation: robt = 0.68 rcrit = 0.64 Chi-Square GOF: χ2obt = 3.24 χ2crit = 4.25
Using a sample that has n=50 pair of data, we get a correlation coefficient r=-0.269 for the following null and alternative hypotheses determine and compute the test statistic value: HO: p=0 H1: pe 0 O a t=7.51 O b. z=7.51 O o.z=-0. 16 Odt=-1.08
Which of the following statistical tools have independent samples? Chi-square Mann-Whitney Wilcoxon Paired t test

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