4.44 Nearsighted: It is believed that nearsightedness affects about 8% of all children. In a random sampleof 194 children, 21 are nearsighted. Conduct a hypothesis test using the 5% significance levela) Construct hypotheses appropriate for the following question: Do these data provide evidence that the 8%value is inaccurate!OH P-0.08H:p> 0.08OH₂:p-0.08Hap<0.08Ho:p=0.08HA:P 0.08b) What proportion of children in this sample are nearsighted? Round your answer to 4 decimal places.c) Given that the standard error of the sample proportion is 0.0195 and the point estimate follows a nearlynormal distribution, calculate the test statistic (use the 2-statistic). Round your answer to 2 decimalplaces.d) What is the p-value for this hypothesis test? Round your answer to 4 decimal places.P.-e) What is the decision for this hypothesis test?Osince pa we reject the null hypothesis and accept the alternativeOsince pa we accept the null hypothesisOsince pa we do not have enough evidence to reject the null hypothesis, so we fail to reject thenull hypothesisOsince pa we fail to reject the null hypothesisSincer

given data claim : p≠0.08 n = 194 x = 21 α = 0.05

Answered: 4.44 Nearsighted: It is believed that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of 400 residents are asked if they are in favor of the proposed 10% vanity tax that will raise badly needed revenue for infrastructure development. If 300 are in favor, test the hypothesis that more than 60% of the voters are in favor of the proposed tax. Using a 0.01 level of significance, what is the appropriate test statistic? Ot=6.12 Ot=-6.12 Oz=6.12 OZ=-6.12
Two groups were selected for an experiment. The sample data is reported: Group A Group B Sample Mean Spending/day ($) 170 150 Sample Standard deviation ($) 10 5 # of Females 9 7 Sample Size 36 42 a. Set up a 99% confidence interval for the mean difference in spending between the two groups. b. At the 10% level test the alternate hypothesis that group B has lower spending level than Group A.
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In a random sample of 63, the proportion of the sample with a certain characteristic was 0.61. What is the 95% confidence interval for pp?
a particular hypothesis test is left-tailed, and the area to the left of the test statistic is 0.20. what is the p-value?
Only 15% of registered voters voted in the last election. Will voter participation increase for the upcoming election? Of the 347 randomly selected registered voters surveyed, 56 of them will vote in the upcoming election. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use z-test for a population proportion b. The null and alternative hypotheses would be: Họ: ? Select an answer (please enter a decimal) H.: ?vSelect an answer v (Please enter a decimal) c. The test statistic ?v (please show your answer to 4 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is v f. Based on this, we should fail to reject g. Thus, the final conclusion is that ... O The data suggest the population proportion is not significantly higher than 15% at a = 0.01, so there is statistically significant evidence to conclude that the percentage of registered voters who will vote in the upcoming election will be equal to 15%. a…
A significance test is conducted for which the alternative hypothesis states that more than 83 percent of all adult sea turtles on a certain beach are female. A random sample of adult sea turtles from the beach found that 85 percent of the sea turtles were female. The pp-value for the test is 0.4058. If the null hypothesis is true, which of the following statements is a correct interpretation of the pp-value? Of all possible samples of the same size, 40.58 percent will result in 85 percent of adult sea turtles on the beach being female. Of all possible samples of the same size, 40.58 percent will result in 85 percent of adult sea turtles on the beach being female., A Of all possible samples of the same size, 40.58 percent will result in 85 percent or more of adult sea turtles on the beach being female. Of all possible samples of the same size, 40.58 percent will result in 85 percent or more of adult sea turtles on the beach being female., B Of all possible…
Answer question 7 and 8
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Question 2: A random sample of 200 observations produced a sample proportion of 0.35. Determine the 98% confidence interval for the population proportion. rt Answer:

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