int index = 0; do{ if(numbers[index]%2 == 1) System.out.println(numbers[index]+" is an odd number."); index++; }while(index < numbers.length); b. for(int a=0 ;a < numbers.length; a +=2){ System.out.println(numbers[a]+" is an odd number.") }
int index = 0; do{ if(numbers[index]%2 == 1) System.out.println(numbers[index]+" is an odd number."); index++; }while(index < numbers.length); b. for(int a=0 ;a < numbers.length; a +=2){ System.out.println(numbers[a]+" is an odd number.") }
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
All the loops below are meant to do the same thing, except...
Select one:
a.
int index = 0;
do{
if(numbers[index]%2 == 1)
System.out.println(numbers[index]+" is an odd number.");
index++;
}while(index < numbers.length);
b.
for(int a=0 ;a < numbers.length; a +=2){
System.out.println(numbers[a]+" is an odd number.")
}
c.
for(int num:numbers){
if(num%2 == 1)
System.out.println(num+" is an odd number.")
}
d.
int index = 0;
while(index < numbers.length){
if(numbers[index]%2 == 1)
System.out.println(numbers[index]+" is an odd number.");
index++;
}
CLEAR MY CHOICE
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