Translate to LEGv8 int count=0;char line[100];for(int i=0; line[i]1="\0'; i++)if(i==0){if((line[i)>='a' && line[i]<='z'))if(line[i]==''{++i;if(line[i)>='a' && line[i]<='z'){line[i]=line[i]-32;continue;else{if(line[i)>='A' && line[i]<='Z')line[i]=line[i)+32;for (int i = 0;line[1] = '\0';i++)%3Dif (line[i] ==' && line[i+1] l= '")count++;

Used fgets() instead of gets() which is deprecated. fgets() takes three paramters: 1. Pointer to…

Answered: Translate to LEGv8

Engineering

Computer Science

Translate to LEGv8

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Translate to LEGv8

int count=0;
char line[100];
for(int i=0; line[i]1="\0'; i++)
if(i==0)
{
if((line[i)>='a' && line[i]<='z'))
if(line[i]==''
{
++i;
if(line[i)>='a' && line[i]<='z')
{
line[i]=line[i]-32;
continue;
else
{
if(line[i)>='A' && line[i]<='Z')
line[i]=line[i)+32;
for (int i = 0;line[1] = '\0';i++)
%3D
if (line[i] ==' && line[i+1] l= '")
count++;

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