int choice1(int x)O a.{return (x < 0);}O b. int choice2(int x){return (x <« 31) & 1;}O . int choice3(int x){return 15 * x;}O d. int choice4(int x){return (x + 15) /4}int choice5(int x){return x / 16;}O f. int choice6(int x){return (x >> 31);} Question 10Select the equivalent C function for thefollowing assembler routine:'002:pushl %ebpmovl %esp,%ebpmovl 8(%ebp),%eax # 8(%ebp) is xtestl %eax,%eaxjge .L4addl $15,%eaxL4:sarl $4,%eaxmovl %ebp,%esppopl %ebpret

The given question are multiple choice selected based question.

Answered: int choice1(int x) а. { return (x < 0);…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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int pertambahan(int pilihan, int now){ int result; result =pilihan + now; return result;} int perkalian(int pilihan, int now){ int result; result = pilihan*now; return result;} int main(){ int NoR,initial; int now; int temp1, temp2; scanf("%d %d", &NoR, &initial); getchar(); now=initial; for(int o=0;o<NoR;o++){ char a,b; int pilihan1,pilihan2; scanf("%c %d %c %d",&a, &pilihan1,&b, &pilihan2); getchar(); if(a=='+') { if(pilihan1>=-1000 && pilihan1<=1000) { temp1 = pertambahan(pilihan1,now); } else{ temp1=-10000; } } else if(a=='x') { if(pilihan1>=-2 && pilihan1<=2){ temp1 = perkalian(pilihan1,now); } else { temp1=-10000; } } if(b=='+') { if(pilihan2>=-1000 && pilihan2<=1000) { temp2 = pertambahan(pilihan2,now); } else {…
Test 10: Check upper board and having bonus correctly (0/3) Test 11: Check upper board and not having bonus correctly (0/3)
What is causing this error?
using System; class Program { publicstaticvoid Main(string[] args) { int number = 1; while (number <= 88) { Console.WriteLine(number); number = number + 2; } int[] randNo = newint[88]; Random r = new Random(); int i=0; while (number <= 88) { randNo[i] = number; number+=1; i+=1; } for (i = 0; i < 3; i++) { Console.WriteLine("Random Numbers between 1 and 88 are " + randNo[r.Next(1, 88)]); } } } this code counts from 1-88 in odds and then selects three different random numbers. it keeps choosing 0 as a random number everytime. how can that be fixed?
int getUpperScore(){ int upperScore = 0; for(int i = ONES; i <= SIXES; i++){ upperScore += score[i]; } return upperScore + getBonusScore(); } //Returns the score of the upper part of the board int getLowerScore(){ int lowerScore = 0; for(int i = THREE_OF_KIND; i <= YAHTZEE; i++){ lowerScore += score[i]; } return lowerScore; } //Returns the bonus points int getBonusScore(){ const int UPPER_SCORES_THRESHOLD = 63; const int BONUS_POINTS = 35; if(getUpperScore() >= UPPER_SCORES_THRESHOLD){ return BONUS_POINTS; } return 0; } //Returns the total score int getTotalScore(){ return getUpperScore() + getLowerScore(); } Test 10: Check upper board and having bonus correctly (0/3) failed
Complete the function ConvertToDecadesAnd Years to convert totalYears to decades and years. Return decades and years using the ElapsedDecades Years struct. Ex: 26 years is 2 decades and 6 years. 1 #include 2 3 typedef struct ElapsedDecadesYears_struct { int decadesVal;` 5 int yearsVal; 6) ElapsedDecadesYears; 7 8 Elapsed Decades Years ConvertToDecadesAndYears(int totalYears) { ElapsedDecades Years tempVal; /* Your code goes here */ 15 int main(void) { 8722878 25 26 } ElapsedDecadesYears elapsedYears; int totalYears; scanf("%d", &totalYears); elapsedYears = ConvertToDecadesAndYears (totalYears); printf("%d decades and %d years\n", elapsedYears.decadesVal, elapsedYears.yearsVal); return 0;
#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…
int funcB(int); int funcA(int n) { if (n 4) { return n* funcA(n - 5); } else { return n- funcB(n - 1); int main() { cout << funcA(13); return 0; What is the output of this program? Please show our work.
int stop = 6; int num =6; int count=0; for(int i = stop; i >0; i-=2) { num += i; count++; } System.out.println("num = "+ num); System.out.println("count = "+ count); } }
CODING LANGUAGE: R (similar to python) R is a programming language for statistical computing and graphics supported by the R Core Team and the R Foundation for Statistical Computing. The Behdel TestThe Bechdel test asks whether a work of fiction features at least two women who talk to each otherabout something other than a man, and there must be two women named characters.In this mini analysis we work with the data used in the FiveThirtyEight story titled:"The Dollar-And-Cents Case Against Hollywood's Exclusion of Women"https://fivethirtyeight.com/features/the-dollar-and-cents-case-against-hollywoods-exclusion-of-women/Start with loading the packages: fivethirtyeight, tidyverse1. What information does this dataset contain? What commands did you use to see this?For our purposes of analysis we will focus our analysis on movies released between 1990 and 2013.bechdel90_13 <- bechdel %>%filter(between(year, 1990, 2013))2. How many movies are in our filtered data set?The…
What value will be returned by the function if a = 8, b=12? %3D int func(int a, int b){ if(a>b){ return a+b; } else if(a
class TenNums {private: int *p; public: TenNums() { p = new int[10]; for (int i = 0; i < 10; i++) p[i] = i; } void display() { for (int i = 0; i < 10; i++) cout << p[i] << " "; }};int main() { TenNums a; a.display(); TenNums b = a; b.display(); return 0;} Continuing from Question 4, let's say I added the following overloaded operator method to the class. Which statement will invoke this method? TenNums TenNums::operator+(const TenNums& b) { TenNums o; for (int i = 0; i < 10; i++) o.p[i] = p[i] + b.p [i]; return o;} Group of answer choices TenNums a; TenNums b = a; TenNums c = a + b; TenNums c = a.add(b);

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int choice1(int x) а. { return (x < 0); } O b. int choice2(int x) { return (x <« 31) & 1; } O c. int choice3(int x) { return 15 * x; } O d. int choice4(int x) { return (x + 15) /4 } int choice5(int x) { return x / 16; } Of. int choice6(int x) {