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- Draw the top, bottom, left, right, back and front view, Dimension and include a title block. The scale is % to 0.582 776 dia counter bore 588 deep 402 dia through hole AN 2renion ne Teth 0. Seis 6niy one 6.8 3-1 5.2 4.515 433 6.10 J9 3.575 2.0625 4,75 の 5 350 2.625 2.34 3.12 12 0. 28125 0.9 375 dia 766 deep. 238 dia 1.00 deep tapped -28 4.57 T.35 0. 1785 the 3.275 0.75 Soie deThe following results were dtaimed during a mild steel test piece of 122mm diateret and 50 mm gauge lenythi %3B lis 28 8 12 |0-0210.0310.04 10:05 10-06 1008 Load 20 24 Esttemsion (mm? lo-01 1. Oraw the load extenfion graph and from. the graph determine', i Strain and stress at elastic limit The modulus of elasticity for the mild stel. ii The utimate tensile fest Iv. The Safety factor.Calculate the Resultant Condition of the HOLE in the drawing below: 1.000 O 1.060 O 1.000 O.530 .982 C 2.000 Ø.995-1.000 +0.008MABC 6.00 O None of these answers is correct X 3.000 Y 01.005-1.030 +0.005MABC B A XX = .01 ANGLES = ± 1°
- 6736.6 is incorrectStress, a (MPa) Strain, e (x10* m/m) Yong Modulus, E (GPa) 3.963 40.0 99.1 7.926 75.0 106 11.89 105.0 113.2 1.85 122.0 130.0 19.81 144,0 137.6 Table 2 Stress and Strain 3|Page Dissections 1. Draw the graph of stress against strain 2. Discusses the obtained results 3. From the graph find. stress ? Yong Modulus, E? 4. Why Compression test is important in industry ?di2.00 PI5. 50 d15. 60 15. 46 10. 06 INVD, UTE SPLIME DATA DETMETTED HARP CORNERT L47 10.04. ®sEr HEAT TREAT
- The following data were collected from a 12 mm diameter test specimen of Magnesium. LOAD (N) GAUEGE LENGTH (mm) 0 5000 10000 15000 20000 25000 26500 27000 26500 30.000 25000 30.0296 30.0592 30.0888 30.15 30.51 30.90 31.50 (maximum load) 32.10 32.79 (fracture) After the fracture, the gauge length is 32.61 mm and the diameter is 11.74 mm. a) What is the elastic modulus? b) Percent elongation at fracture? c) Percent elongation after fracture? d) What is the Poisson's ratio? e)Draw the engineering stress-strain diagram corresponding to the values in the table. Call this plot I. Now consider this experiment is repeated at a higher temperature with an identical sample. Draw the new engineering stress-strain diagram, call it plot II and highlight the differences (on the same graph) between I and II.The following data were collected from a test specimen of cold-rolled and annealed brass. The specimen had an initial gage length 10 of 35 mm and an initial cross-sectional area A0 of 10.5 mm2. Load, N Elongation, mm Load, N Elongation Al, mm 0.0000 1350 5.55 66 0.0112 1720 8.15 177 0.0157 2220 13.07 327 0.0199 2690 (maximum load) 22.77 462 0.0240 2410 25.25 (fracture) 797 1.72 (a) Plot the engineering stress-strain curve and the true stress-strain curve. Use a software graphing Package. (b) Calculate the 0.2% offset yield strength; Calculate the tensile strength; Calculate the elastic modulus using a linear fit to the appropriate data. (c) Can you use the equations that calculate the true stresses and true strains beyond the ultimate tensile strength? Why? If the true stress-strain data were known past the point of necking, what might the curve look like?Graph the following data on a stress-strain curve. Identify/Determine the following: Elastic Limit, Plastic Limit, Proportional Limit, Upper Yield Point, Lower Yield Point, Ultimate Strength, Rupture Strength, and Modulus of Elasticity. Engr. True Stress Strain o, MPa 102.3 0.00050 204.7 0.00102 293.5 0.00146 272.9 0.00230 264.0 0.00310 268.9 0.00500 267.6 0.00700 264.0 0.01000 318.6 0.0490 372.0 0.1250 394.4 0.2180 395.0 0.2340 384.2 0.3060 360.4 0.3300 327.5 0.3480 290.0 0.3600 266.8 0.3660
- -100 A1 25 20 D- 92 A3 200 1. What is the value of ybar from the 1-1 line [ Select] 2. What is the value of centroidal MOI Ixx? [ Select ] 3. What is the value of centroidal MOI lyy? [ Select ] 8+81b) A sedan car weights 2100 kg with 45:55 distributions front to rear. The car has wheelbase of 1.9 m. With aid of following table showing the tyre cornering stiffness values for different loads: Load Cornering Stiffness (kg/deg) 300 131 400 149 500 174 600 203 i) Calculate the cornering coefficient for the front and rear tyres. ii) Calculate the understeering gradient. iii) Determine whether it is understeer or over steer. iv) Calculate critical or characteristic speed.Check the correct statements regarding the picture. * ALT HDG MDA 310 260 240 10 220 10 200 2150 ANH 1024 ITLE 109.10 It says the aircraft is below the glide slope It is a picture of the navigational display It says the aircraft is perfectly aligned with the center of the runway It says the aircraft is to the right of the runway and not centered 10 o o 3000 。>025- - FD 2 230 >020- 20 80 07