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#include using namespace std; char* duplicateWithoutBlanks(char *word) { int len = sizeof(word); char *new_str = new char[len + 1]; int k = 0; for (int i = 0; i < len; ++i) { if (word[i] != ' ') new_str[k++] = word[i]; } new_str[k] = '\0'; return new_str; } int main() { // Testing code char word[] = "Hello, World!"; char* result = duplicateWithoutBlanks(word); cout<< "word: "<< word<< "\nResult: "<< result; ; return 0; }     What to change to out put the same word without blank?

#include using namespace std; char* duplicateWithoutBlanks(char *word) { int len = sizeof(word); char *new_str = new char[len + 1]; int k = 0; for (int i = 0; i < len; ++i) { if (word[i] != ' ') new_str[k++] = word[i]; } new_str[k] = '\0'; return new_str; } int main() { // Testing code char word[] = "Hello, World!"; char* result = duplicateWithoutBlanks(word); cout<< "word: "<< word<< "\nResult: "<< result; ; return 0; }     What to change to out put the same word without blank?

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question

#include <iostream>
using namespace std;

char* duplicateWithoutBlanks(char *word)
{
int len = sizeof(word);

char *new_str = new char[len + 1];

int k = 0;

for (int i = 0; i < len; ++i)
{
if (word[i] != ' ')
new_str[k++] = word[i];
}

new_str[k] = '\0';

return new_str;
}


int main()
{
// Testing code

char word[] = "Hello, World!";

char* result = duplicateWithoutBlanks(word);

cout<< "word: "<< word<< "\nResult: "<< result;

; return 0;
}

 

 

What to change to out put the same word without blank?

Expert Solution
Step 1

Program changes: 

Make the method duplicateWithoutBlanks() void.

char* str and counter k is suffice. 

Change the condition in for loop. Make it as word[i] instead of using len variable. 

Call the method in main and print the result.

 

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