In this experiment you studied the following net chemical reaction that we will call reaction (1): H,0, + 2 H* + 21 - I, + 2 H,0 (1) with the following proposed three-step reaction mechanism: H,0, +IOH + HOI OH + H- H,0 HOI + H + 1 + H,0 Step 1: (slow) Step 2: (very fast) Step 3: (fast) In neutral solution containing only hydrogen peroxide and iodide ion, a different net chemical reaction occurs: 2 H,0, - 2 H,0 + 0,(g) (2) The following three-step reaction mechanism has been proposed to explain reaction (2): Step 1: (slow) H,O, +1 - OH + HOI Step 2a: (very fast) OH + HOI - 10 + H,0 H202 + 10 1+ H20 + 0,(g) 2 H202 - 2 HzO + OCJ) Show that when you sum the three reaction steps the net result is reaction (2): Step 3a: (fast) What would be the expected rate law for the reaction mechanism, assuming that the rate of reaction (2) is limited by the slow Step 1? Is the expected rate law for reaction (2) the same as or different from the rate law you determined for reaction (1)?

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In this experiment you studied the following net chemical reaction that we will call reaction (1):
H,0, + 2 H* + 21 - 1, + 2 H,0
(1)
with the following proposed three-step reaction mechanism:
Step 1: (slow)
H,0, +1 - OH + HOI
Step 2: (very fast)
OH + H* - H,0
Step 3: (fast)
HOI + H* + - 2 + H,0
In neutral solution containing only hydrogen peroxide and iodide ion, a different net chemical reaction
occurs:
2 H,0, - 2 H,0 + 0,(g)
(2)
The following three-step reaction mechanism has been proposed to explain reaction (2):
Step 1: (slow)
H20, +1 - OH + HOI
Step 2a: (very fast) OH + HOI -- 10- + H,0
H,0, + 10 -I + H20 + 0,(g)
2 H2 02 → 2 HzO + OLCJ)
Show that when you sum the three reaction steps the net result is reaction (2):
Step 3a: (fast)
What would be the expected rate law for the reaction mechanism, assuming that the rate of reaction (2) is
limited by the slow Step 1?
Is the expected rate law for reaction (2) the same as or different from the rate law you determined for
reaction (1)?
Transcribed Image Text:In this experiment you studied the following net chemical reaction that we will call reaction (1): H,0, + 2 H* + 21 - 1, + 2 H,0 (1) with the following proposed three-step reaction mechanism: Step 1: (slow) H,0, +1 - OH + HOI Step 2: (very fast) OH + H* - H,0 Step 3: (fast) HOI + H* + - 2 + H,0 In neutral solution containing only hydrogen peroxide and iodide ion, a different net chemical reaction occurs: 2 H,0, - 2 H,0 + 0,(g) (2) The following three-step reaction mechanism has been proposed to explain reaction (2): Step 1: (slow) H20, +1 - OH + HOI Step 2a: (very fast) OH + HOI -- 10- + H,0 H,0, + 10 -I + H20 + 0,(g) 2 H2 02 → 2 HzO + OLCJ) Show that when you sum the three reaction steps the net result is reaction (2): Step 3a: (fast) What would be the expected rate law for the reaction mechanism, assuming that the rate of reaction (2) is limited by the slow Step 1? Is the expected rate law for reaction (2) the same as or different from the rate law you determined for reaction (1)?
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