d[H] |[Br][H, -0 - ka dt [Br][H2] [H] Br, [H][HBr [H][HBr]| d[Br] -0- kl 2 E Br., 2[Brz] - k | Br| H, [Br][H2]| [H][Br, + ka [H]|Brg]| [H][HBr [H][HBr]| + kal [Br]² [Br]? Step 3 of 8 Sum the equations for dHI and dBri and solve for (Br). (Use the following as necessary: [Br2), [H], [H2), [HBr), ki, k2, k3, ka, and ks.) dt dt (Br) =

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Step 2 of 8
Assuming that the reaction chain proceeds according to the elementary steps below, apply the steady state approximation to both the H and Br atoms. (Use the following as necessary: [Br], [Br2], [H], [H2], and [HBr], or
enter 0 if the term does not apply.)
rate constant
reaction type
elementary reaction
Br2 - 2 Br
k1
chain initiation
Br + H2 - HBr + H
k2
chain propagation
H + Br2 - HBr + Br
k3
chain propagation
H + HBr - H2 + Br
K4
chain inhibition
Br + Br - Br2
k5
chain termination
Br][H2
d[H] = 0 = k2
[Br][H2]
dt
[H][Br.
- k3
[H][Br2]
HHB°
[H][HBr]
- kal
2
d[Br]
= 0 = k1l Br2
dt
2[Br||
Br] H2
- kal
[Br][H2]
H Br2
+ k3
[H][Br]
+ ka [H]|HBr
[H][HBr]
- ks[Br]2
[Br]?
Step 3 of 8
d[H]
d[Br]
and solve for [Br]. (Use the following as necessary: [Br2], [H], [H2], [HBr], k1, k2, k3, k4, and k5.)
and
Sum the equations for
dt
dt
[Br] =
Transcribed Image Text:Step 2 of 8 Assuming that the reaction chain proceeds according to the elementary steps below, apply the steady state approximation to both the H and Br atoms. (Use the following as necessary: [Br], [Br2], [H], [H2], and [HBr], or enter 0 if the term does not apply.) rate constant reaction type elementary reaction Br2 - 2 Br k1 chain initiation Br + H2 - HBr + H k2 chain propagation H + Br2 - HBr + Br k3 chain propagation H + HBr - H2 + Br K4 chain inhibition Br + Br - Br2 k5 chain termination Br][H2 d[H] = 0 = k2 [Br][H2] dt [H][Br. - k3 [H][Br2] HHB° [H][HBr] - kal 2 d[Br] = 0 = k1l Br2 dt 2[Br|| Br] H2 - kal [Br][H2] H Br2 + k3 [H][Br] + ka [H]|HBr [H][HBr] - ks[Br]2 [Br]? Step 3 of 8 d[H] d[Br] and solve for [Br]. (Use the following as necessary: [Br2], [H], [H2], [HBr], k1, k2, k3, k4, and k5.) and Sum the equations for dt dt [Br] =
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