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In the free radical chlorination of isobutane, what is the % yield of product X and Y, respectively? H CH3 CH3 + HC- H - | A. X=64%, Y=36% B. X=36%, Y=64% C. X=60%, Y=40% D. X=40%, Y=60% E. X=trace (<1%), Y=>99% F. X=28%, Y=72%

In the free radical chlorination of isobutane, what is the % yield of product X and Y, respectively? H CH3 CH3 + HC- H - | A. X=64%, Y=36% B. X=36%, Y=64% C. X=60%, Y=40% D. X=40%, Y=60% E. X=trace (<1%), Y=>99% F. X=28%, Y=72%

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In the free radical chlorination of isobutane, what is the % yield of product X and Y, respectively? dzz H-Ċ-C H CH3 -CI t HC-ċ-CH2 H CH3 H H A. X=64%, Y=36% B. X=36%, Y=64% C. X=60%, Y=40% D. X=40%, Y=60% E. X=trace (<1%), Y=>99% F. X=28%, Y=72%
Transcribed Image Text:In the free radical chlorination of isobutane, what is the % yield of product X and Y, respectively? dzz H-Ċ-C H CH3 -CI t HC-ċ-CH2 H CH3 H H A. X=64%, Y=36% B. X=36%, Y=64% C. X=60%, Y=40% D. X=40%, Y=60% E. X=trace (<1%), Y=>99% F. X=28%, Y=72%
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