23, Н C=C H The halogenation reaction above will always produce H-C-C-H Br Br + Br2 - `H isomers. a. cis- b. trans- c. both cis- and trans- d. neither cis- nor trans-
23, Н C=C H The halogenation reaction above will always produce H-C-C-H Br Br + Br2 - `H isomers. a. cis- b. trans- c. both cis- and trans- d. neither cis- nor trans-
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 23:**
In the reaction shown, a hydrocarbon reacts with bromine (\(Br_2\)) to form a dibromo compound. The structural formula of the reactant is drawn as:
\[
\begin{array}{c}
H \quad H \\
\backslash / \\
C = C \\
/ \backslash \\
H \quad H \\
\end{array}
\]
The product is shown as:
\[
\begin{array}{c}
H \quad H \\
\backslash / \\
C - C \\
/ \backslash \\
Br \quad Br \\
\end{array}
\]
**Text:**
"The halogenation reaction above will always produce ______ isomers."
**Options:**
- a. cis-
- b. trans-
- c. both cis- and trans-
- d. neither cis- nor trans-
The reaction shown involves the addition of bromine (\(Br_2\)) across the double bond of ethene to form 1,2-dibromoethane. This addition results in a molecule that does not have any geometric isomerism (cis-trans isomerism) because the product does not have a double bond or a planar structure necessary for such isomerism. Hence, the correct answer is:
**d. neither cis- nor trans-**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff55a1131-b1e4-4ec9-baae-097574f2cab0%2F81254674-621b-46b1-948e-c576d2456c9e%2Fuxgegcv_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 23:**
In the reaction shown, a hydrocarbon reacts with bromine (\(Br_2\)) to form a dibromo compound. The structural formula of the reactant is drawn as:
\[
\begin{array}{c}
H \quad H \\
\backslash / \\
C = C \\
/ \backslash \\
H \quad H \\
\end{array}
\]
The product is shown as:
\[
\begin{array}{c}
H \quad H \\
\backslash / \\
C - C \\
/ \backslash \\
Br \quad Br \\
\end{array}
\]
**Text:**
"The halogenation reaction above will always produce ______ isomers."
**Options:**
- a. cis-
- b. trans-
- c. both cis- and trans-
- d. neither cis- nor trans-
The reaction shown involves the addition of bromine (\(Br_2\)) across the double bond of ethene to form 1,2-dibromoethane. This addition results in a molecule that does not have any geometric isomerism (cis-trans isomerism) because the product does not have a double bond or a planar structure necessary for such isomerism. Hence, the correct answer is:
**d. neither cis- nor trans-**
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