OAODОвC In the figure below, Km is indicated at position labeled_BUInitial velocity (μM product/s)50454035201550050D100150 200[S] (μm)High [E]Low [E]A250 300 350

Km is Michaelis menton constant that corresponds to the substrate concentration at half maximal…

Answered: In the figure below, Km is indicated at…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Blue line Km VALUE, VMAX 180
please show and explain how to find Km, Vmax and Ki value with this chart. Please show work and explanation please!
Orders: Kphos 30 mmol in 100 mL NS over 4 hours via central line KCl 40 mEq in 100 mL NS over 2 hours via central line Mg gluconate in 9 g in 500 mL NS over 9 hours via central line Solutions: K - 80mEq Phos - (0.32 x 86kg) = 27.52 or 30 mmol Mg - (0.1 x 86kg) = 8.6g or 9g Calcium corrected Ca - or ionized level = 8.1 + [{4-2.6} x 0.8] = 9.22 My questions are - HOW IS POTASSIUM (K) IS CALCULATED TO GET 80 mEq and How is Magnesium (Mg) is calculated?
What term describes kcat/Km? What is the maximum valuethat this term can have? Explain.
Determine the % inaccuracy by calculating the percent error of the micropipette at the set volume of 100 µL A. Standard deviation B. Covieffecrnt of varaiant C. % error (precision) Percent error = mean volume delivered -expected volume x 100 Expected volume RUN Weight Measurement (in g) 1 0.0985 2 0.0987 3 0.0985 4 0.0982 5 0.0984 6 0.0984 7 0.0981 8 0.0983 9 0.0982 10 0.0988 Total 0.9841 A. Standard deviation B. Covieffecrnt of varaiant C. % error (precision)
Calculate the Vmax with the parameters given. All parameters may not be needed to calculate. Kcat = 130 s^-1 Vo = 3.0 μMs^-1 S = 10 μM Et = 0.15 µM
The momentum or “impetus” of a 12 kilogram mass moving at 7 meters per second can be stopped completely by a direct collision with a 3-kilogram mass moving at a velocity of: 14 meters per second 28 meters per second 36 meters per second 63 meters per second 84 meters per second
Consider the following reaction at 25°C with the ΔG°’ = +1800 J/mol for the forward reaction.The molar concentrations at the beginning of the reaction were [A] = 19 mM and [B] = 10 mM.After 1 hour, the concentrations were [A] = 16 mM and [B] = 13 mM. Calculate the ΔG of the reaction at the 1 hour timepoint. Please round to 1 decimal point.Gas constant = 8.315 J/mol K
When Galileo Galilei pushed a ball down an inclined plane, it had an initial velocity (vo) of 4.0 meters per second (time = 0 seconds) and a final velocity (vf) of 10.0 meters per second (time = 2 seconds). How far did the ball travel along the inclined plane in these 2 seconds? 14 meters 20 meters 28 meters 40 meters 84 meters
please provide an example to solve for Velocity using the Michaelis-Menten Equation ?
The experiment is about testing the ideal gas law (magnesium ribbon experiment)
According to Jean Buridan’s equation, the momentum or “impetus” of an 88 kilogram mass moving at 5 meters per second would be: 110 kilogram-meters per second 220 kilogram-meters per second 440 kilogram-meters per second 660 kilogram-meters per second 880 kilogram-meters per second

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In the figure below, Km is indicated at position labeled B Initial velocity (μM product/s) 50 45 40 35 20 15 5 0 0 50 D 100 150 200 [S] (μm) High [E] Low [E] 250 300 350