In the electron configuration of inner transition metal Pr, the designation of the orbital with the highest energy is Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a 4f b 6p 2d d 7f e 5s

In the electron configuration of inner transition metal Pr, the designation of the orbital with the highest energy is Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a 4f b 6p 2d d 7f e 5s

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The question is in the image.
Part A: How does ionization energy change down a group? increases from left to right decreases from left to right increases from top to bottom decreases from top to bottom Part B: Why is Ionization energy smaller for larger atoms? Sheilding. The nucleus cannot hold onto the electrons as well and loses them easier Shielding. The nucleus holds onto the electrons stronger and does not lose them easily There is no explanation Part C: According to the trend, which of these 4 elements has the largest ionization energy? Be (atomic# 4) Sr (atomic# 38) F (atomic# 9) I (atomic# 53) Part D: According to the trend, which of these 4 elements has the smallest ionization energy? Be (atomic# 4) Sr (atomic# 38) F (atomic# 9)…
Select the statement(s) that explain(s) the relationship between the arrangement of elements by size and first ionization energy. 1. The first set of paired electrons in a pp subshell experience a large amount of electron-electron repulsion, making the fourth electron in a pp subshell easy to remove. 2. The third unpaired electron in a pp subshell causes a lot of electron-electron repulsion among the orbitals, making the third electron in a pp subshell easy to remove. 3. A pp subshell with only one unpaired electron is extremely stable, making the fifth electron in a pp subshell easy to remove. 4. The two arrangements are the same because IE of elements increases from left to right and the radii of elements decreases from left to right. 5. A full ss subshell is able to shield a newly filled pp subshell from the nucleus, making the first electron in a pp subshell easy to remove.