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Fill in the blanks for the shorthand electron configuration as follows: Aluminum would be [Ne]3s^2 2p^1 Mn2+:[Ar] Mn4+:[Ar] Rh2+:[Kr] Ru3+:[Kr] 100

Fill in the blanks for the shorthand electron configuration as follows: Aluminum would be [Ne]3s^2 2p^1 Mn2+:[Ar] Mn4+:[Ar] Rh2+:[Kr] Ru3+:[Kr] 100

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Fill in the blanks for the shorthand electron configuration as follows: Aluminum would be [Ne]3s^2 2p^1 Mn2+:[Ar] Mn4+:[Ar] Rh2+:[Kr] Ru3+:[kr] Check
Transcribed Image Text:Fill in the blanks for the shorthand electron configuration as follows: Aluminum would be [Ne]3s^2 2p^1 Mn2+:[Ar] Mn4+:[Ar] Rh2+:[Kr] Ru3+:[kr] Check
Expert Solution
Step 1: Find the atomic numbers of the given elements

The atomic number of Mn = 25

The atomic number of Rh = 45

The atomic number of Ru = 44

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