In the circuit shown in Figure 10.19, the voltage V₁ can be writtenas V₁ = V11 + V12, where V₁1 is from Vs when Is is deactivated, andV12 is from Is when Vs is deactivated. Find V₁1 and V12.ZLj11 26820⁰ VR10 Ω10 20⁰ AFigure 10.19a. V11 = 30.77-j33.85 V, V12 = 54.75 + j49.77 VO b. V11 = 20.77-j33.85 V, V12 = 64.75 + j49.77 VO c. V11 = 25.77-j33.85 V, V12 = 59.75 + j49.77 VO d. V11 =15.77-j33.85 V, V12 = 69.75 + j49.77 V

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In the circuit shown in Figure 10.19, the voltage V₁ can be written as V₁ = V11 + V12, where V₁1 is from Vs when Is is deactivated, and V12 is from Is when Vs is deactivated. Find V₁1 and V₁2- ZL 111 Ω 6820⁰ V R 10 Ω 10 20⁰ A Figure 10.19 O a. V11 = 30.77-j33.85 V, V12 = 54.75 + j49.77 V O b. V11 = 20.77-j33.85 V, V12 = 64.75 + j49.77 V O c. V11 = 25.77-j33.85 V, V12 = 59.75 + j49.77 V O d. V11 =15.77-j33.85 V, V12 = 69.75 + j49.77 V

In the circuit shown in Figure 10.19, the voltage V₁ can be written as V₁ = V11 + V12, where V₁1 is from Vs when Is is deactivated, and V12 is from Is when Vs is deactivated. Find V₁1 and V₁2- ZL 111 Ω 6820⁰ V R 10 Ω 10 20⁰ A Figure 10.19 O a. V11 = 30.77-j33.85 V, V12 = 54.75 + j49.77 V O b. V11 = 20.77-j33.85 V, V12 = 64.75 + j49.77 V O c. V11 = 25.77-j33.85 V, V12 = 59.75 + j49.77 V O d. V11 =15.77-j33.85 V, V12 = 69.75 + j49.77 V

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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