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TRANSCRIBE THE SOLUTION IN DIGITAL FORMAT

TRANSCRIBE THE SOLUTION IN DIGITAL FORMAT

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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TRANSCRIBE THE SOLUTION IN DIGITAL FORMAT

... ਦੇ 5+j10 8 ਦਿਨਾਂ ਹੈ । (ਸਾਰ) ਦੀ 5-jlo ' | ੨੦ 2 5+10 fib t 20 ਹੈ ਤੇ ਦੀ * ਹੇਠ ਲੈ " sto [ 4 S 4. 00000 V 7 V " ਤੇ "ਸ਼ 20 V V 60,000 To find it L) + 60, CE¹ -1X5 25 604-50109 11 4 60,000 20 0.0q-jo•0% . 012 /-13° 2 8.33 241.63 5+10 • 3344 ( 3 hts Ze3% 0.74 L41.63-63.43 © .74 l. 8 O K 25 ਵੰਸੀ J 20 | 14) = 0.14 «S(5੦੮-੨ | 2 1 : 8 ) oKA ☬ 5. AM 20m H ( 0 .
Transcribed Image Text:... ਦੇ 5+j10 8 ਦਿਨਾਂ ਹੈ । (ਸਾਰ) ਦੀ 5-jlo ' | ੨੦ 2 5+10 fib t 20 ਹੈ ਤੇ ਦੀ * ਹੇਠ ਲੈ " sto [ 4 S 4. 00000 V 7 V " ਤੇ "ਸ਼ 20 V V 60,000 To find it L) + 60, CE¹ -1X5 25 604-50109 11 4 60,000 20 0.0q-jo•0% . 012 /-13° 2 8.33 241.63 5+10 • 3344 ( 3 hts Ze3% 0.74 L41.63-63.43 © .74 l. 8 O K 25 ਵੰਸੀ J 20 | 14) = 0.14 «S(5੦੮-੨ | 2 1 : 8 ) oKA ☬ 5. AM 20m H ( 0 .
soli for the given .C The value of Angular frequence ī N₁ = 2000s (5001) ->Reactance offered by Inductor is given by XL = GWL xi XL = =j5 500*20*16 X/₁ = 5104 104 10 x₁ = √1052² Vs 20tes(c) 2010 -20 20 3 + 20-2 20 V M V Source V₂ = 2000s (500-1) 60,000 5+j10 } " (20 " 60,000+ • 5+j10 --Apply Natal -omaly sic @ Node + W бека = $60,000 5.2 л O 20 20 V w=5001 20.2 M KiL 3310 in 310 52 M з бока
Transcribed Image Text:soli for the given .C The value of Angular frequence ī N₁ = 2000s (5001) ->Reactance offered by Inductor is given by XL = GWL xi XL = =j5 500*20*16 X/₁ = 5104 104 10 x₁ = √1052² Vs 20tes(c) 2010 -20 20 3 + 20-2 20 V M V Source V₂ = 2000s (500-1) 60,000 5+j10 } " (20 " 60,000+ • 5+j10 --Apply Natal -omaly sic @ Node + W бека = $60,000 5.2 л O 20 20 V w=5001 20.2 M KiL 3310 in 310 52 M з бока
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