In class, we derived the effective control of the form L = −kpsign(894)691:3-ka(1±89:3891:3)w (1) for the regulation case. Prove that it provides asymptotic stability with the reaction wheels.
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- What is the minimum dampening ratio for an underdamped system such that its overshoot is limited to 10%? This image is my scratch work based of an in-class problem. I'm unsure of the steps and the final equation for Zeta. It also puts out a different number that my professor wrote…Use the equivalent systems method to derive the differential equation governing the motion of the bar shown in the figure, when the bar subjected to clockwise angular displacement from the equilibrium position. Assume small and consider the translational displacement of the center of the bar. kQ.1 Develop an analytical reasoning to prove that the mechanism as shown in Figure.1 have mobility. (a) Figure 1 TTT
- plz solve correctly using Finite Element Analysis best wishes tonFind the global stiffness matrix, displacement at node 1&2, reaction forces at 1&4, and force in spring for the following figure shown below. N ki=90 mm k2=1800, mm N k3=80, P=600 N and mm U1=U4=0 k, k, P ks 1 2 4Write the global stiffness matrix of the spring assemblage shown. Assume that all springs remain horizontal, the vertical bars at nodes 2 and 3 are rigid and allowed to slide horizontally to the left or right. Node 1 K1 = 2000 lb/in K2 = 2000 lb/in Node 2 m K3 = 1500 lb/in K4 = 1500 lb/in Node 3 F = 250 lb ma K5 = 3000 lb/in Node 4
- Do not answer in image format. Maintain accuracy and quality in your answer. Answer completely.Determine with the finite element method the magnitude of the reaction force at node 3 of the following bar-spring system. Consider k = 2x10^6 N/m, L = 2 m, E = 70 GPa, A = 0.001 m^2, P = 20 kN F3x O k = --- / 2 P -8 625.32 N -18 918.90 N O-10 081.07 N -12 523.86 N -16 425.89 N EA L 335 üzerinden işaretenmiş P Soruyu işarete Henüz cevaplanmadı Fss rininininn. 3) For the spring assemblage shown below Figure, obtain (a) the global stiffness matrix, (b) the displacements of nodes 2-4, (c) the global nodal forces. Node 1 is fixed while node 5 is given a fixed, known displacement 5 = 200 mm. The spring constants are all equal to k = 200 kN/m.
- 35. A horizontal spring attached to a wall has a force constant QC of k = 850 N/m. A block of mass m = 1.00 kg is attached to the spring and rests on a frictionless, horizontal sur- face as in Figure P8.35. (a) The block is pulled to a posi- tion x, = 6.00 cm from equilibrium and released. Find the elastic potential energy stored in the spring when the block is 6.00 cm from equilibrium and when the block passes through equilibrium. (b) Find the speed of the block as it passes through the equilibrium point. (c) What is the speed of the block when it is at a position x,/2 = 3.00 cm? (d) Why isn't the answer to part (C) half the answer to part (b)? k wwwwwww m x= 0 x= x;/2 X= X; Figure P8.35Hello, please solve this problem. Thank you.2- Derive the rule-of-mixtures expression for the composite extensional modulus E₁ assuming the existence of an interphase region. The starting point for the derivation would be the model shown below. For simplicity, assume the interphase, like the matrix, is isotropic with modulus E¹. With an interphase region there is a volume fraction associated with the interphase (i.e.,V;). For this situation: vf + vm + vi = 1 H |w²||wm|