In a study of the decomposition of ammonia on a platinum surface at 856 °C NH3-1/2 N₂ + 3/2 H₂ the following data were obtained: [NH3], M seconds 5.79x10-3 0 2.90x10-3 998 1.45x10-3 7.25x10-4 1.50x10³ 1.75x10³ Hint: It is not necessary to graph these data. (1) The observed half life for this reaction when the starting concentration is 5.79x10-3 M is starting concentration is 2.90x10-³ M is (2) The average rate of disappearance of NH3 from t = 0 s to t = 998 s is (3) The average rate of disappearance of NH3 from t = 998 s to t = 1.50x10³ s is (4) Based on these data, the rate constant for this order reaction is M s 1. M s 1. Ms¹. s and when the

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In a study of the decomposition of ammonia on a platinum surface at 856 °C
NH3-1/2 N₂ + 3/2 H₂
the following data were obtained:
[NH3], M
seconds
5.79x10-3
0
2.90x10-3
998
1.45x10-3
1.50x10³
Hint: It is not necessary to graph these data.
(1)
The observed half life for this reaction when the starting concentration is 5.79x10-3 M is
starting concentration is 2.90x10-³ M is
7.25x10-4
1.75x10³
S.
(4)
Based on these data, the rate constant for this
(2)
The average rate of disappearance of NH3 from t = 0 s to t = 998 s is
(3)
The average rate of disappearance of NH3 from t = 998 s to t = 1.50x10³ s is
order reaction is
M s ¹.
M s ¹.
Ms¹.
s and when the
Transcribed Image Text:In a study of the decomposition of ammonia on a platinum surface at 856 °C NH3-1/2 N₂ + 3/2 H₂ the following data were obtained: [NH3], M seconds 5.79x10-3 0 2.90x10-3 998 1.45x10-3 1.50x10³ Hint: It is not necessary to graph these data. (1) The observed half life for this reaction when the starting concentration is 5.79x10-3 M is starting concentration is 2.90x10-³ M is 7.25x10-4 1.75x10³ S. (4) Based on these data, the rate constant for this (2) The average rate of disappearance of NH3 from t = 0 s to t = 998 s is (3) The average rate of disappearance of NH3 from t = 998 s to t = 1.50x10³ s is order reaction is M s ¹. M s ¹. Ms¹. s and when the
Expert Solution
Step 1

time

[NH3]

0

5.79 × 10–3

998

2.90 × 10–3

1.50 ×103

1.45 × 10–3

1.75 ×103

7.25 ×10–4

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