In a study of the gas phase decomposition of dinitrogen pentoxide at 335 K N,O5(g)2 NO,(g) + ½ 02(g) the concentration of N,Og was followed as a function of time. It was found that a graph of In[N,O5] versus time in seconds gave a straight line with a slope of -6.30×10-3 s-1 and a y-intercept of -1.74 . Based on this plot, the reaction is V order in N,O5 and the rate constant for the reaction is
In a study of the gas phase decomposition of dinitrogen pentoxide at 335 K N,O5(g)2 NO,(g) + ½ 02(g) the concentration of N,Og was followed as a function of time. It was found that a graph of In[N,O5] versus time in seconds gave a straight line with a slope of -6.30×10-3 s-1 and a y-intercept of -1.74 . Based on this plot, the reaction is V order in N,O5 and the rate constant for the reaction is
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![In a study of the gas phase decomposition of dinitrogen pentoxide at 335 K:
\[ \text{N}_2\text{O}_5(\text{g}) \rightarrow 2 \, \text{NO}_2(\text{g}) + \frac{1}{2} \, \text{O}_2(\text{g}) \]
the concentration of \(\text{N}_2\text{O}_5\) was followed as a function of time.
It was found that a graph of \(\ln[\text{N}_2\text{O}_5]\) versus time in seconds gave a straight line with a slope of \(-6.30 \times 10^{-3} \, \text{s}^{-1}\) and a y-intercept of \(-1.74\).
Based on this plot, the reaction is \(\boxed{\phantom{0}}\) order in \(\text{N}_2\text{O}_5\) and the rate constant for the reaction is \(\boxed{\phantom{0}}\) \(\text{s}^{-1}\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc211686a-894f-4228-909b-4643e31f0284%2F080d375e-c4a9-4d93-8a91-32a75c7f94f0%2Fzh2n6z9_processed.png&w=3840&q=75)
Transcribed Image Text:In a study of the gas phase decomposition of dinitrogen pentoxide at 335 K:
\[ \text{N}_2\text{O}_5(\text{g}) \rightarrow 2 \, \text{NO}_2(\text{g}) + \frac{1}{2} \, \text{O}_2(\text{g}) \]
the concentration of \(\text{N}_2\text{O}_5\) was followed as a function of time.
It was found that a graph of \(\ln[\text{N}_2\text{O}_5]\) versus time in seconds gave a straight line with a slope of \(-6.30 \times 10^{-3} \, \text{s}^{-1}\) and a y-intercept of \(-1.74\).
Based on this plot, the reaction is \(\boxed{\phantom{0}}\) order in \(\text{N}_2\text{O}_5\) and the rate constant for the reaction is \(\boxed{\phantom{0}}\) \(\text{s}^{-1}\).
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